 | Joseph Ray - 1857 - 348 σελίδες
...its root on the right. like a quotient in division. Subtract the square of this root from the left period, and to the remainder bring down the next period for a dividend. 3. Double the .root found, and place it on the left for a trial divisor. Find how many times the divisor... | |
 | Benjamin Greenleaf - 1857 - 336 σελίδες
...the left-hand period, and place its root on • the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by ZOO for a divisor, by which divide the dividend, and... | |
 | Charles Guilford Burnham - 1857 - 342 σελίδες
...quotient in division. Place the square of the root found, under said period, and subtract it therefrom, and to the remainder bring down the next period, for a dividend. III. Double the root already found, for a divisor ; see hoie often the divisor is contained in the... | |
 | Joseph Ray - 1857 - 408 σελίδες
...right, after the manner of a quotient in division. Subtract the square of the root from the left per'od, and to the remainder bring down the next period for a dividend. 3rd. Double the root already found, and place it on the left for a divisor. Find how many times the... | |
 | Benjamin Greenleaf - 1857 - 452 σελίδες
...period, and write its root as the first figure of the required root. From that period subtract the cube, and to the remainder bring down the next period for a dividend. Multiply the square of the root figure by 3, and to the product annex two ciphers for a trial divisor,... | |
 | Benjamin Greenleaf - 1858 - 332 σελίδες
...in the left-hand period, and place its root on the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by 300 for a divisor, by which divide the dividend, and... | |
 | Benjamin Greenleaf - 1858 - 456 σελίδες
...period, and trrite its root as the jirst figure of the required root. From that period subtract the cube, and to the remainder bring down the next period for a dividend. Multiply the, square of the root figure by 3, and to the product annex tiro ciphers for a trial diviior,... | |
 | Charles Haynes Haswell - 1858 - 350 σελίδες
...left-hand period, and place its root in the quotient ; subtract the square number from the left-hand period, and to the remainder bring down the 'next period for a new dividend. Double the root already found for a divisor ; find how many times this incomplete divisor... | |
 | Horatio Nelson Robinson - 1859 - 362 σελίδες
...left hand period, and write its root for the first figure in the root ; subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. Fig. III. 70 i Two Divisors = 140 1 70. 3 Complete Divisor = 143 III. At the left of the dividend write... | |
 | Horatio Nelson Robinson - 1860 - 444 σελίδες
...left hand period, and write its root for the first figure in the required root; subtract, the cube from the left hand period, and to the remainder bring down the next period for a dividend. III. At the left of the dividend write three times the square of tlie first figure of the root, and-... | |
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Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained in the dividend... 
