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" Equal oblique lines from a point to a plane meet the plane at equal distances from the foot of the perpendicular ; and of two unequal oblique lines the greater meets the plane at the greater distance from the foot of the perpendicular. "
Plane and Solid Geometry - Σελίδα 148
των James Howard Gore - 1898 - 210 σελίδες
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Schultze and Sevenoak's Plane and Solid Geometry

Arthur Schultze, Frank Louis Sevenoak - 1913 - 486 σελίδες
...triangles. 2. Elf = EA2 + AT?, EC* = EA2 + AC*. 510. COR. 1. Conversely, equal oblique lines drawn from a point to a plane meet the plane at equal distances from the foot of the perpendicular from the point to the plane, and of two unequal oblique lines, the greater one meets the plane at a...

Solid Geometry

Sophia Foster Richardson - 1914 - 236 σελίδες
...perpendicular. 85. COROLLARY 2. If oblique lines to a plane from a point in a perpendicular to the plane meet the plane at equal distances from the foot of the perpendicular, they are equal. 86. COROLLARY 3. If a plane is perpendicular to one of two parallel lines, it is perpendicular...

Constructive Text-book of Practical Mathematics, Τόμος 2

Horace Wilmer Marsh, Annie Griswold Fordyce Marsh - 1914 - 270 σελίδες
...line. VIII THEOREM 16 Equal oblique lines drawn to a plane, from a point in a perpendicular to the plane, meet the plane at equal distances from the foot of the perpendicular. VIII THEOREM 17 The greater of two unequal oblique lines drawn to a plane, from a point in a perpendicular...

Solid Geometry

John Charles Stone, James Franklin Millis - 1916 - 196 σελίδες
...AFE > Z AEF, etc. Write the proof in full. 311. Theorem. — (1) Equal oblique line-segments drawn from a point to a plane meet the plane at equal distances from the foot of the perpendicular from the point ; (2) of two unequal line-segments, the greater meets the plane at the greater distance...

Plane and Solid Geometry

William Betz - 1916 - 536 σελίδες
...the one cutting off the greater distance is the greater; and conversely, equal oblique lines cut off equal distances from the foot of the perpendicular, and of two unequal oblique lines the greater line cuts off the greater distance. A (a) Given AB perpendicular to the plane P at B, the lines BC...

Solid Geometry

William Betz, Harrison Emmett Webb - 1916 - 214 σελίδες
...the one cutting off the greater distance is the greater; and conversely, equal oblique lines cut off equal distances from the foot of the perpendicular, and of two unequal oblique lines the greater line cuts off' the greater distance. Why? §233 (a) Given AB perpendicular to the plane P at B, the...

Solid Geometry

John H. Williams, Kenneth P. Williams - 1916 - 184 σελίδες
...PROPOSITION IV. THEOREM 614. // lines are drawn from a point in a perpendicular to a plane: (1) two that meet the plane at equal distances from the foot of the perpendicular are equal; (2) two that meet the plane at unequal distances from the foot of the perpendicular are...

Solid Geometry

Fletcher Durell, Elmer Ellsworth Arnold - 1917 - 220 σελίδες
...446. I. Two oblique straight lines drawn from a point to a plane are equal when, and only when, they meet the plane at equal distances from the foot of the perpendicular drawn from the point to the plane ; II. Of two oblique lines drawn from a point to a plane, and meeting...

Schultze and Sevenoak's Plane and Solid Geometry

Arthur Schultze, Frank Louis Sevenoak - 1918 - 486 σελίδες
...triangles. 2. Elf = El2 + AT?, EC2 = EA2 + AC2. 510. COR. 1. Conversely, equal oblique lines drawn from a point to a plane meet the plane at equal distances from the foot of the perpendicular from the point to the plane, and of two unequal oblique lines, the greater one meets the plane at a...

Solid Geometry, with Problems and Applications

Herbert Ellsworth Slaught, Nels Johann Lennes - 1919 - 240 σελίδες
...meeting the plane at equal distances from the foot of the perpendicular are equal ; and conversely, two equal oblique lines from a point to a plane meet the...equal distances from the foot of the perpendicular. (1) Given PC -LM, and AC = BC. To prove that PA = PB. Suggestion. Prove A PCA = A PCB. (2) Given PC...




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