 | Elias Loomis - 1873 - 396 σελίδες
...Multiply the divisor thus increased by the last figure of the root ; subtract the product from Hie dividend, and to the remainder bring down the next period for a new dividend. 6th. Take three hundred times the square of the whole root now found for a new trial divisor, and by... | |
 | Charles Davies - 1874 - 346 σελίδες
...root and also annex it to the divisor. IV. Multiply the divisor thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down (he next period for a new dividend. "V. Double the whole root thus found, for a new trial divisor,... | |
 | Horatio Nelson Robinson - 1874 - 340 σελίδες
...correction, and the result will be the complete divisor. V. Multiply the complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder bring down another period for a new dividend. VI. Add together the square of the last figure of the root, the... | |
 | Horatio Nelson Robinson - 1875 - 338 σελίδες
...root and at the right of the divisor. IV. Miiltiply the divisor thus completed by the last, figure of the root ; subtract the product from the dividend,...the next period for a new dividend. V. Double the right-hand figure of the last complete divisor for a new divisor, and continue tiie operation as before.... | |
 | Lorenzo Fairbanks - 1875 - 472 σελίδες
...the right of the divisor. IV. Multiply the divisor thus obtained by the digit of the root last found: subtract the product from the dividend, and to the...the next period for a new dividend. V. Double the part of the root already found, for a new divisor, and proceed as before ; and so on, through all the... | |
 | Horatio Nelson Robinson - 1875 - 430 σελίδες
...to the trial divisor for a complete divisor ; multiply the complete divisor by the trial figure in the root, subtract the product from the dividend,...bring down the next period for a new dividend. V. Take the last complete divisor, doubling its right-hand figure, for a new trial divisor, with which... | |
 | Horatio Nelson Robinson - 1875 - 462 σελίδες
...result will be the complete divisor. V. Multiply the complete divisor by the trial figure ; subtract Hie product from the dividend, and to the remainder bring down the next period for a new dividend. VI. Add the square of the last figure of the rool,t the last term in column II, and the complete divisor... | |
 | William Guy Peck - 1875 - 348 σελίδες
...the trial divisor for a complete divisor. IV. Multiply the divisor thus completed by the trial figure of the root, subtract the product from the dividend, and to the remainder annex the -following period for a new dividend. V. Proceed as before, continuing the operation till... | |
 | Horatio Nelson Robinson - 1875 - 468 σελίδες
...to the trial divisor for a complete divisor ; multiply the complete divisor by the trial figure in the root, subtract the product from the dividend, and to the remainder briny down the next period for a new dividend. V. Multiply the last figure of the last complete divisor... | |
 | Thomas Henderson - 1876 - 114 σελίδες
...30, and also the square of the last figure. Multiply the complete divisor by the last root figure, subtract the product from the dividend, and to the remainder bring down the next period, if any, or add three cyphers, for a new dividend. To the last complete divisor add the two numbers... | |
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Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
