 | Horatio Nelson Robinson - 1850 - 256 σελίδες
...31, and the sum of the squares of the first and last is 626. What are the numbers ? Am. \, 5, 25. 12. It is required to find three numbers in geometrical...progression, such that their sum shall be 14, and the sum of tfaeir squares 84. Ans. 2, 4, and 8. 13. There are four numbers in geometrical progression, the second... | |
 | John Bonnycastle - 1851 - 288 σελίδες
...consequently, x = — 6 + V (36 + 45) = — 6 + 9 = 3, by the rule. Whence the numbers are 3, 7, 1], and 15. 8. It is required to find three numbers^ in geometrical...sum shall be 14, and the sum of their squares 84. Let •#, y, and z % be the three numbers, Then, xz = y 2 , by the nature of proportion, And i^lf^+^ri^-J... | |
 | 1855 - 424 σελίδες
...geometrical progression may be solved, as in other parts of algebra, by means of equations. Prob. 10. Find three numbers in geometrical progression, such that their sum shall be 14, aud the sum of their squares Let the three numbers be *, y, and z. By the conditions, 2 : у : : у... | |
 | John Radford Young - 1855 - 218 σελίδες
...8x=3500-7x :. 15*=3500 .'. x= .'. y=500-*=266| "Tenee the shares are 233Z. 6s. 8d. and 266Z. 13«. 4d. (2) Find three numbers in geometrical progression such that their sum shall be 7 and the sum of their squares 21. Let the numbers be x, y, and z ; then by the question x + y + z=7... | |
 | Horatio Nelson Robinson - 1858 - 372 σελίδες
...geometrical progression is 148, and the sum of the second and fourth is 888. What are the numbers ? T. It ¡a required to find three numbers in geometrical progression,...sum shall be 14, and the sum of their squares 84. Ana.' Z, 4, and 8. 8. There are four numbers in geometrical progression, the second of which is less... | |
 | Benjamin Greenleaf - 1864 - 420 σελίδες
...we have x2 ± 12 a: = 45 Whence, x = ±3, or ±15. Hence, the four numbers are 3, 7, 11, and 15. 2. It is required to find three numbers in geometrical...sum shall be 14, and the sum of their squares 84. SOLUTION. Let x and y denote the two extremes ; then \/ ' xy is the mean, and by the conditions, =i4... | |
 | Horatio Nelson Robinson - 1864 - 444 σελίδες
...the second and fourth is 888. What are the numbers '(til y'Vy * *У 3An». 4, 24, 144, and 864. л 7. It is required to find three numbers in geometrical...sum shall be 14, and the sum of their squares 84. Ans. 2, 4, and 8. 5. There are four numbers in geometrical progression, the second of which is less... | |
 | Thomas Kimber - 1865 - 302 σελίδες
...in the line above, .-. 10 у = (3 у + 6) Whence у* — - у = — , У о у = 3 and ж = 2. (6) It is required to find three numbers in geometrical progression, such, that their sum shall be 7, and the sum of thoir squares 21. Let -, x, and ж у be the numbers ; y Then - + x + xy = 7 (1)... | |
 | Horatio Nelson Robinson - 1866 - 328 σελίδες
...and the sum of the squares of the first and last is 626 ; what are the numbers ? Ans. 1, 5, 25. 12. It is required to find three numbers in geometrical...sum shall be 14, and the sum of their squares 84. Ans. 2, 4, and 8. 13. Of four numbers in geometrical progression, the second number is less than the... | |
 | Horatio Nelson Robinson - 1868 - 430 σελίδες
...148, and the sum of the second and fourth is 888. What are the numbers? Ans. 4, 24, 144, and 864. 7. It is required to find three numbers in geometrical...sum shall be 14, and the sum of their squares 84. Ans. 2, 4, and 8. 8. There are four numbers in geometrical progression, the second of which is less... | |
| |
It is required to find three numbers in geometrical progression, such that their sum shall be 14, and the sum of their squares 84. 
