 | Benjamin Greenleaf - 1851 - 332 σελίδες
...perpendicular, the side AC the hypolhenuse, and the angle at B is a right angle. ART. 272. In every right angled triangle the square of the hypothenuse is equal to the sum of the squares of the base and perpendicular, as shown by the following diagram. It will be seen by examining... | |
 | Horace Mann - 1851 - 384 σελίδες
...lines 10ft. apart. This mode of operation is founded on the property of right-angled triangles, that the square of the hypothenuse is equal to the sum of the squares of the other two sides. A roof is said to have a true pitch, when the length of each rafter... | |
 | William Smyth - 1851 - 272 σελίδες
...the other two sides ? NOTE. In solving this and other similar questions, it will be recollected that the square of the hypothenuse is equal to the sum of the squares of the other two sides, and the area is equal to one half the product of these sideS. ANS.... | |
 | Edward Deering Mansfield - 1851 - 348 σελίδες
...in the year five hundred and ninety before Christ, who discovered the fundamental proposition that the square of the hypothenuse is equal to the sum of the squares of the other two sides. Euclid appeared in the year three hundred BC His object was to systematize... | |
 | Charles William Hackley - 1851 - 536 σελίδες
...and a very simple formula depending upon the well-known property of the right angled triangle, that the square of the hypothenuse is equal to the sum of the squares of the other two sides, a formula expressing the value of the sine of half an arc in terms... | |
 | Jeremiah Day - 1851 - 418 σελίδες
...referred to. 94. Other relations of the sine, tangent, &c., may be derived from the proposition, that the square of the hypothenuse is equal to the sum of the squares of the perpendicular sides. (Euc. 47. 1.) In the right angled triangles CBG, CAD, and CHP,... | |
 | Thomas Kentish - 1852 - 258 σελίδες
...29, and raise a perpendicular BC = 17. Join AB; apply it to the scale, and it will be found 33.6. For the square of the hypothenuse is equal to the sum of the squares of the base and perpendicular. It is required to find the diameter of a copper, that, being... | |
 | Adolfo de Castro y Rossi - 1853 - 290 σελίδες
...triangle rectangle;' " or with an Englishman who reads the same thing in his own language thus : " ' The square of the hypothenuse is equal to the sum of the squares of the two other sides of a rectangle triangle! " Thirdly, those who read in a well-known tongue,... | |
 | Thomas Lund - 1854 - 520 σελίδες
...perimeter. OBS. It is to be observed that the proposition proved in (43, Part I.), viz. that in any right-angled triangle the square of the hypothenuse is equal to the sum of the squares of the sides bounding the right angle, is of continual application in Mensuration, and enables... | |
 | George Ticknor Curtis - 1854 - 718 σελίδες
...ia applicable, are truths of exact science ; as the well-known propositions of geometry, that, in a right-angled triangle, the square of the hypothenuse is equal to the sum of the squares of the opposite sides ; that the angle at the centre of a circle is double the angle at the... | |
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The square of the hypothenuse is equal to the sum of the squares of the other two sides ; as, 5033 402+302. 
