 | Edward Atkins - 1876 - 130 σελίδες
...CE — DB. /ADC. BDC> VCD. ^BCD. ZBDC = and> /BCD. i KCD = (. t'DC. Proposition 7. — Theorem. Upon the same base, and on the same side of it, there cannot bs two triangles tJiat have their sides, which are terminated in one extremity of the base, equal to... | |
 | Robert Potts - 1876 - 446 σελίδες
...on the saute side of it, there cannot bt two triangles that have their sides which are terminated in one extremity of the base, equal to one another, and likewise those which are terminated in the Other extremity. If it be possible, on the same base AB, and upon the same... | |
 | Edward Atkins - 1877 - 72 σελίδες
...mi the same side of it, there cannot be two triangles that have their sides, which are terminated in one extremity of the base, equal to one another, and likewise those which are terminated in the other extremity. Let the triangles ACB, ADB, upon the same base AB, and... | |
 | Euclides - 1877 - 58 σελίδες
...CA do not coincide with the sides ED, FD, they wil have a different situation as EG, FG : but then on the same base and on the same side of it there will be two triangles having their sides which are terminated in the one extremity of the base equal... | |
 | Stephen Thomas Hawtrey - 1878 - 202 σελίδες
...ACB, needs no demonstration, for it is B evident from Ax. 9 that BC cannot be equal to B D. Therefore on the same base and on the same side of it there cannot be two triangles which have the two sides terminated in one extremity of the base equal to each other, and likewise... | |
 | Edward Harri Mathews - 1879 - 94 σελίδες
...straight line. t Draw the figure for the case where the given point is in the straight line produced. 3. On the same base, and on the same side of it, there cannot be two triangles which have their sides, which are terminated in one extremity of the base, equal to one another, and... | |
 | Moffatt and Paige - 1879 - 426 σελίδες
...etc. QED COR. Hence every equiangular triangle is also equilateral. Proposition VII. Theorem. Upon the same base, and on the same side of it, there cannot be two triangles which have their sides that are terminated in one extremity of the base equal to one another, and also... | |
 | Henry Crocker Marriott WATSON - 1879 - 280 σελίδες
...MAESTON, SBAKLB, & RIVINGTON, CROWN BUILDINGS, 188, FLEET STREET. 1879. [All rights reserved. ] . " Upon the same base, and on the same side of it, there cannot be two triangles that have their sides which are terminated in one extremity of the base, equal to one another, and... | |
 | W J. Dickinson - 1879 - 44 σελίδες
...What proposition is the converse of this. Show that every equiangular triangle is equilateral. 7. Upon the same base and on the same side of it there cannot be two triangles that have their sides which are terminated in one extremity of the base equal to one another, and likewise... | |
 | Euclides - 1879 - 146 σελίδες
...sides BA, AC do not coincide with the sides ED, DF, but have a different situation as EG, FG ; Then, on the same base and on the same side of it there can be two As which have their sides which are terminated at one extremity of the base equal to one... | |
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Upon the same base, and on the same side of it, there cannot be two triangles that have their sides which are terminated in one extremity of' the base, equal to one another, and likewise those which are terminated in the other extremity. 
