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" ... subtract the product from the dividend, and to the remainder annex the next period for the next dividend. "
First Course in Algebra - Σελίδα 238
των Walter Burton Ford, Charles Ammerman - 1919 - 334 σελίδες
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The Normal Elementary Algebra, Μέρος 1

Edward Brooks - 1901
...COMPLETE DIVISOR. V. Multiply the COMPLETE DIVISOR by the last term of the root ; subtract the product from the dividend, and to the remainder annex the next period for a new dividend. Take 3 times the square of the root now found, regarded as tens, for a trial divisor,...

New Practical Arithmetic

Eugene L. Dubbs - 1901 - 440 σελίδες
...complete divisor. 5. Multiply the complete divisor by the last figure in the root ; subtract the product from the dividend, and to the remainder annex the next period for another dividend. 6. Square the part of the root now found, multiply the product by 300, find the next...

Advanced Algebra for Colleges and Schools

William James Milne - 1902 - 608 σελίδες
...figure last found, multiply this complete divisor b>/ the figure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all tJte periods have been used. TJie result icill be lite square root...

The Model Practical Arithmetic

Edward Gideon - 1902 - 256 σελίδες
...complete divisor. V. Multiply the complete divisor by the last figure of the root ; subtract the product from the dividend, and to the remainder annex the next period, for a new dividend. VI. Proceed in the same manner with all the periods to the last. The result will be...

Complete Graded Arithmetic: Third grade-[eighth grade], Τόμος 8

George Edward Atwood - 1902
...to the divisor. Multiply the completed divisor by the last figure of the root, subtract the product from the dividend, and to the remainder annex the next period for a new dividend, continuing the process until all the periods have been used. NOTE. — If any partial...

Arithmetic for Business with Short Methods and Rapid Calculations in All ...

Jacob Henry Minick, Clement Carrington Gaines - 1904 - 398 σελίδες
...complete divisor. Multiply the complete divisor by the second figure of the root and subtract the product from, the dividend, and to the remainder annex the next period for the next dividend. Take three times the square of the root already found for a second trial divisor, find the third figure...

The Foundations of Higher Arithmetic

Benjamin Franklin Sisk - 1905 - 203 σελίδες
...the trial term. 7. Multiply the complete divisor by the trial term in the root, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. STEPS: POWERS AND ROOTS EXAMPLES 1. What is the cube root of 13144256? OPERATION. 1st...

Progressive Arithmetic: Third Book, Βιβλίο 3

William James Milne - 1906 - 366 σελίδες
...figure last found, multiply this divisor by the figure of the root last found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all the periods have been used. The result will be the square root sought....

Progressive Arithmetic, Βιβλίο 3

William James Milne - 1906
...figure last found, multiply this divisor by the figure of the root last found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. 1. When the number is not a perfect square, annex periods of decimal ciphers and continue the process....

Arithmetic: Instruction Paper, Τόμος 3

Charles Wilbur Leigh - 1906
...divisor, and multiply the new divisor, their sum, by the last figure in the root. Subtract this product from the dividend, and to the remainder annex the next period for the new dividend. After annexing a cipher to that part of the root already found, and doubling the result,...




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