 | Frederick Emerson - 1839 - 300 σελίδες
...the divisor completed. Lastly — Multiply the divisor thus completed, by the figure last placed in the root, and subtract the product from the dividend; and to the remainder bring down the next period for a new dividend. Thus proceed, till the whole root is extracted. Observe,... | |
 | George Roberts Perkins - 1841 - 274 σελίδες
...at the right of the TRIAL DIVISOR ; the result will be the TRUE DIVISOR. Multiply the true divisor by this second figure of the root, and subtract the...the dividend, and to the remainder annex the next period,for a SECCUD DIVIDEND. . ft IV. To the last TRUE DIVISOR, add the Jastfgure of the root, for... | |
 | John Husband (math. master, Berwick.) - 1841 - 126 σελίδες
...together these two lines for the complete divisor; multiply the sum by the second figure in the root ; subtract the product from the dividend, and to the remainder annex the third period for a new dividend. Place the square of the second figure of the root under the complete... | |
 | Charles Davies - 1842 - 284 σελίδες
...the root and also at the right of the divisor. IV. Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. But if any of the products should be greater than the... | |
 | Charles Davies - 1842 - 368 σελίδες
...the root and also at the right of the divisor. IV. Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Double the whole root already found, for a new divisor,... | |
 | 1843 - 142 σελίδες
...product write also the square of the trial-figure, then multiply the sum of these by the trial-figure, subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. EVOLUTION.ciphers for a new divisor, with which find anolner trialfigure, and proceed as before. 1.... | |
 | Charles DAVIES (LL.D.) - 1843 - 348 σελίδες
...the root and also at the right of the divisor. IV. Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. But if the product should exceed the dividend, diminish... | |
 | Charles Davies - 1844 - 666 σελίδες
...the root and also at the right of the divisor. IV. Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. But if tlie product should exceed the dividend, diminish... | |
 | Davis Wasgatt Clark - 1844 - 394 σελίδες
...the root, and also at the right of the divisor. IV. Multiply the divisor thus augmented by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Double the whole root already found for a new divisor,... | |
 | Charles Davies - 1844 - 356 σελίδες
...also at the right of the divisor. IV. Multiply ihe divisor, thus augmented, by the last figure oftiie root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. But if the product should exceed the dividend, diminish... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
