 | Joseph Ray - 1866 - 420 σελίδες
...tlic hist figure; the sum will be the complete divisor. 4th. Multiply the complete divisor by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, and so proceed until all the periods arc brought down.... | |
 | Joseph Ray - 1852 - 422 σελίδες
...the last figure; the sum will be the complete divisor. 4th. Multiply the complete divisor by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, and so proceed until all the periods are brought down.... | |
 | Charles Davies - 1867 - 322 σελίδες
...root and also at the right of the divisor. IV. Multiply the divisor, thus augmented, by the lastfyurt of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. But if any of the products should be greater than the... | |
 | John Fair Stoddard - 1888 - 480 σελίδες
...right, to the last term of the 2d column for the TBUE DIVISOK. Multiply this divisor lij the last term of the root, and subtract the product from the dividend, and to the remainder annex the next period, for the SECOND DIVIDEND. 6. Proceed in like manner till all the periods have been used. NOTE.— 1. If... | |
 | William Frothingham Bradbury - 1868 - 264 σελίδες
...right of the trial divisor for the TRUE DIVISOR. Multiply the true divisor by this new root figure, . subtract the product from the dividend, and to the...remainder annex the next period, for a new dividend. NOTE 1. — When a root figure is 0, annex 0 also to the trial divisor, and bring down the next period... | |
 | William Frothingham Bradbury - 1868 - 270 σελίδες
...trial divisor, and the SUM will be the TRUE DIVISOR. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a dividend. Find a new trial divisor, and proceed as before, until all (he periods have been employed.... | |
 | John Fair Stoddard - 1868 - 428 σελίδες
...the square of the second, and the sum will be the TRUE DIVISOE. 5. Multiply the true divisor by the second figure of the root, and subtract the product from the dividend, and bring down the next period for a 2d DIVIDEND. 6. Take 300 times the square of the figures of the root... | |
 | Stoddard A. Felter - 1868 - 360 σελίδες
...the trial divisor, will form the complete dieisor. V. Multiply and subtract as in simple division, and, to the remainder, annex the next period for a new dividend. VI. Proceed in the same way, until all the periods are brouglit down. NOTES. — 1-. If the dividend... | |
 | Robert Stewart (of Dundee.) - 1871 - 248 σελίδες
...the sum of these three numbers is the complete divisor, which multiply by the last quotient figure ; subtract the product from the dividend, and to the...remainder annex the next period for a new dividend, to which find a divisor as before, and proceed in the same manner till all the periods are exhausted.... | |
 | Henry Beadman Bryant, Emerson Elbridge White, Corydon Giles Stowell - 1872 - 576 σελίδες
...trial divisor; the sum will be the true divisor. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. 5. Add twice the root figure last found to the last term in column 1st ; then add the square of the... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
