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" To measure a Parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area or superficial content. "
Felter's New Intermediate Arithmetic: Containing Oral and Written Problems ... - Σελίδα 209
των Stoddard A. Felter, Samuel Ashbel Farrand - 1875 - 258 σελίδες
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Pike's System of Arithmetic Abridged: To which are Added Appropriate ...

Nicolas Pike, Dudley Leavitt - 1826 - 214 σελίδες
...DUODECIMALS. /. To find the superficial contents of boards, fyc. where length and breadth only are considered. RULE. — Multiply the length by the breadth, and the product will be the superficial content. NOTE. — If the board or plank is tapering, add the width of both ends together,...

Arithmetic: In which the Principles of Operating by Numbers are Analytically ...

Daniel Adams - 1848 - 322 σελίδες
...multiply the number of squares in one row by the number of rows ; 5X3=15 square rods, Ans. Hence the RULE. Multiply the length by the breadth, and the product will be the square contents. NOTE. — Three times a line 5 rods long is aline 15 rods long. Hence the pupil must...

Pike's System of Arithmetic Abridged: To which are Added Appropriate ...

Nicolas Pike, Dudley Leavitt - 1826 - 222 σελίδες
...superficial contents of boards, Sfc where length and jbreadlh only are considered. i! i 1.'• — Multiply the length by the breadth, and the product will be the tuperficial content. NOTK. — If the hoard or plank i* tapering, add (he width of liotlv end* together,...

The Improved Arithmetic: Newly Arranged and Clearly Illustrated, Both ...

Daniel Parker - 1828 - 358 σελίδες
...of land, which is 30 rods squaw? Ans. 900. ARTICLE II. To measure a parallelogram, or long square. Rule. — Multiply the length by the breadth, and the product will be the area. Examples. 1. A hall, in the form of a parallelogram, is 80 feet long and 60 wide j how many square...

Daboll's Schoolmaster's Assistant

Nathan Daboll - 1828 - 268 σελίδες
...rods, and 676-5-1 60 =4o. 36r. the Jlnswer. AHT. 2. To measure a Parallelogram, or long square. RULS. Multiply the length by the breadth, and the product will be the area or superficial content. RXAMVI.E8. 1. A certain garden, in form of a lone square, is % ft. long. and...

A Short System of Practical Arithmetic: Compiled from the Best Authorities ...

William Kinne - 1829 - 246 σελίδες
...acre .• therefore =4ac. 36 rods. 160- Ans. CASE 2. — To measure a parallelogram, or long square. RULE — Multiply the length, by the breadth, and the product will be the area, or superficial content, in the same name as that, in which the dimension was taken, whether inches,...

Daboll's Schoolmaster's Assistant: Improved and Enl. ...

Nathan Daboll - 1829 - 252 σελίδες
...sq. rods, and 676-;- 160=4 a. 36 r. the Answer. ART. 2. To measure a parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area, or superficial content. EXAMPLES. 1. A certain .garden, in form of a long square, is фб feet long,...

An Introduction to Mensuration and Practical Geometry

John Bonnycastle - 1829 - 256 σελίδες
...required. TIMBER MEASURE. PROBLEM I. To find the area, or superficial content of a board or plank. RULE. MULTIPLY the length by the breadth, and the product will be the content required. Note. — When the board is tapering, add the breadths of the two ends together,...

A London Encyclopaedia, Or Universal Dictionary of Science, Art ..., Τόμος 22

Thomas Curtis - 1829 - 878 σελίδες
...are destituí« of timber of their own growth. Woodward. To find the superficial content of a plank, multiply the length by the breadth, and the product will be the required content. Ejumple. — The content of a board whose lentil is 5ft. 7in. and breadth 1ft. lOin.,...

The Teacher's Assistant, and Scholar's Mathematical Directory: Containing ...

Dudley Leavitt - 1830 - 154 σελίδες
...weights must 8+5+3 = 16 be in the other scale. MENSURATION OF PLANES. 1 . To find the area or content of a square or parallelogram.* Rule. Multiply the length by the breadth. Exam. What is the content of a parallelogram 40 .rods long, and SO rods wide ? 40x30=1200 rods, and...




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