 | Charles Davies - 1840 - 262 σελίδες
...the more accurate methods by means of figures. PROBLEM I. 2. To find the area of a board or plank. RULE. Multiply the length by the breadth, and the product will be the content required.' Q.OEsT. — 1. What methods of measuring timber have already been explained ? 2.... | |
 | Benjamin Greenleaf - 1841 - 334 σελίδες
...from its verteX, or top, perpendicular to its base. MENSURATION OF SUPERFICIES AND SOLIDS. PROBLEM I. To find the area of a square or parallelogram. RULE....Multiply the length by the breadth and the product is the superficial contents. \. What are the contents of a board 15 feet long, and 2 feet wide ? Ans.... | |
 | Charles Guilford Burnham - 1841 - 324 σελίδες
...thickness. The area is reckoned so many square inches, square feet, square yards, or square rods, &c. To find the area of a square, or parallelogram. RULE. Multiply the length by the breadth, or perpendicular height, and the product will be the area. 1. How many square rods in a field 28 rods... | |
 | William Ruger - 1841 - 268 σελίδες
...w'de, and 20ft. long? Ans. 80yds. NOTE. — To obtain the surface of a plane, as a floor, Jield, if-e. Multiply the length by the breadth, and the product will be the surface ; then as the number of square feet in a yard of the carpeting which is 4,5 feet, is to one... | |
 | Benjamin Greenleaf - 1842 - 184 σελίδες
...weight of an apple 12 inches in circumference ? Ans. 128 ounces. Section JO. GEOMETRICAL PROBLEMS. 1. To find the area of a square or parallelogram. RULE....Multiply the length by the breadth, and the product is the superficial contents. 2. To find the area of a rhombus or a rhomboid. 3. To find the area of... | |
 | Nathan Daboll - 1843 - 254 σελίδες
...acres.] Ans. 26 acres I r. 25 rods. PROB. ii. — To find the area of a parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area. EXAMPLES. 1. How many square yards of ground are contained in a garden which is 126 feet long and 65... | |
 | Benjamin Greenleaf - 1844 - 204 σελίδες
...weight of an apple 12 inches in circumference ? Ans. 128 ounces. Section 5O. GEOMETRICAL PROBLEMS. 1. To find the area of a square or parallelogram. RULE....Multiply the length by the breadth, and the product is the superficial contents. 2. To find the area of a rhombus or rhomboid. RULE. Multiply the length... | |
 | Benjamin Greenleaf - 1844 - 208 σελίδες
...weight of an apple 12 inches in circumference ? Ans. 128 ounces. Section 5O. GEOMETRICAL PROBLEMS. 1. To find the area of a square or parallelogram. RULE....Multiply the length by the breadth, and the product is the superficial contents. 2. To find the area of a rhombus or rhomboid. RULE. Multiply the length... | |
 | William Watson (of Beverley.) - 1845 - 188 σελίδες
...MENSURATION OF SURFACES. PROBLEM 1. — To find the area of a square, rectangle, parallelogram, SfC. * RULE. — Multiply the length by the breadth, and the product will be the area, or multiply half the sum of the parallel sides by their perpendicular distance. EXAMPLES. 1. What is... | |
 | Almon Ticknor - 1846 - 274 σελίδες
...sides are perpendicular to each other (right-angled), but the adjacent sides are longer and parallel. RULE. Multiply the length by the breadth, and the product will be the answer. 1 . A garden is 76 feet in length, and 42 feet in width ; how many square feet of ground are... | |
| |
To measure a Parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area or superficial content. 
