 | Euclid, Robert Simson - 1821 - 514 σελίδες
...draw a straight line AC making any angle with AB; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to be ci t off from it: join BC, and draw DE parallel to cut it: then AE is the part required to be cut off.... | |
 | John Playfair - 1826 - 326 σελίδες
...and take AC A Mieh that it shall eontain AD, as oft as AB is to eontain the part, whieh is to be eut off from it; join BC, and draw DE parallel to it: then AE is the part required to be eut off. Beeause ED is parallel to one of the sides of the triangle ABC, viz. to BC, CD : DA " DE :... | |
 | Robert Simson - 1827 - 546 σελίδες
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to be cut oft' from it ; join BC, and draw DE parallel to it: then AE shall be the part required to be cut off.... | |
 | John Playfair - 1833 - 346 σελίδες
...and take AC such that it shall contain AD, as oft as AB is to contain the part, which is to be cutoff from it ; join BC, and draw DE parallel to it : then AE is the part required to be cut off. Because ED is parallel to one of the sides of the triangle ABC, viz. to BC, CD : DA : : DE : EA (2.... | |
 | Euclides - 1834 - 518 σελίδες
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to...it ; join BC, and draw DE parallel to it : then AE shall be the part required to be cut off. f The triangles ADB, ADC, being both equiangular to ABC,... | |
 | Euclid - 1835 - 540 σελίδες
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to...to it: Then AE is the part required to be cut off. Because ED is parallel to one of the sides of the triangle ABC, viz. to BC, as CD is to DA, so is1... | |
 | Robert Simson - 1835 - 544 σελίδες
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to be cut off from it; join BC, A and draw DE parallel to it : Then AE l\ is the part required to be cut off. / \ Because ED is parallel... | |
 | John Playfair - 1836 - 148 σελίδες
...draw a straight line AC making any angle with AB ; and in AC take any point D, and takeAC the same multiple of AD, that AB is of the part which is to...to it : then AE is the part required to be cut off. Because ED is parallel to one of the sides of the triangle ABC, viz. to BC, as CD is to DA, so is (3.... | |
 | Euclid, James Thomson - 1837 - 410 σελίδες
...book. t Draw a straight line AC making any angle with AB ; in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to be cut off from it ; A join BC, and (I. 31.) draw DE parallel to it : AE N is the part required. T"\ Because ED is parallel... | |
 | Andrew Bell - 1837 - 290 σελίδες
...with AB ; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part A •which is to be cut off from it ; join BC, and draw l\ DE parallel to it ; then AE is the part required X/~V to be cut off. / \ Because ED is parallel... | |
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AC the same multiple of AD, that AB is of the part which is to be cut off from it : join BC, and draw DE parallel to it : then AE is the part required to be cut off. 
