 | Euclid - 1838 - 470 σελίδες
...draw a straight line AC making any angle with AB ; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to be cut off A from it : join BC, and draw DE parallel to it : then AE is the part required to be cut off. Because... | |
 | Robert Simson - 1838 - 434 σελίδες
...draw a straight line AC making any angle with AB ; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to be cut off A from it : join BC, and draw DE parallel to it : then AE is the part required to be cut off. Because... | |
 | Euclides - 1841 - 378 σελίδες
...required, Let AB be the given straight line; it is required to cut off any part from it. part which U to be cut off from it; join BC, and draw DE parallel to CB: then AE shall be the part required to be cut off Because ED is parallel to BC, one of the sides... | |
 | John Playfair - 1842 - 332 σελίδες
...; and in AC take any point D, and take AC such that it shall contain AD, as oft as AB is to contain the part, which is to be cut off from it ; join BC,...to it : then AE is the part required to be cut off. Because ED is parallel to one of the sides of the 17 B c DA : DC (4. 6.) BA : BD (46.) CA : CD (46.).... | |
 | Euclides - 1842 - 320 σελίδες
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take A c the same multiple of AD, that AB is of the part which is to be cut off from it ; join B, c, and draw DE parallel to it (31. 1.) : then AE is the part required to be cut off. ' " " Because... | |
 | Euclid - 1845 - 218 σελίδες
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the / same multiple of AD, that AB is of the part which is to...to it : then AE is the part required to be cut off. Because ED is parallel to one of the sides of the triangle ABC, viz. to BC ; as CD is to DA, so * 2.... | |
 | Euclides - 1845 - 546 σελίδες
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to...cut off from it ; join BC, and draw DE parallel to CB. Then AE shall be the part required to be cut off. Because ED is parallel to BC, one of the sides... | |
 | Euclid, James Thomson - 1845 - 380 σελίδες
...it. Draw a straight line AC making any angle with AB ; in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to be cut off from it ; .join BC, and (I. 31) draw DE parallel to it: AE is the part required. Because ED isparallel to BC, one of the sides... | |
 | Euclides - 1846 - 292 σελίδες
...a straight line AC, making any angle with A. 13 ; and in AC take any point D, and take AC the same multiple of AD that AB is of the part which is to...DE parallel to it : then AE is the part required. For, because ED is parallel to BC, one of the sides of the triangle ABC, therefore BE is to EA as CD... | |
 | John Playfair - 1846 - 334 σελίδες
...; and in AC take any point D, and take AC such that it shall contain AD, as oft as AB is to contain the part, which is to be cut off from it ; join BC,...to it: then AE is the part required to be cut off. 130 triangle ABC, viz. to BC, CD : DA : : BE : EA (2. 6.) ; and by composition (18. 5), CA : AD : :... | |
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AC the same multiple of AD, that AB is of the part which is to be cut off from it : join BC, and draw DE parallel to it : then AE is the part required to be cut off. 
