 ... the first term of the quotient ; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor...  The Elements of Algebra - Σελίδα 85των Elias Loomis - 1856 - 268 σελίδεςΠλήρης προβολή - Σχετικά με αυτό το βιβλίο
 | Herbert Ellsworth Slaught, Nels Johann Lennes - 1908 - 520 σελίδες
...quotient is the first term of the quotient. 3. Multiply the first term of the quotient by the divisor and subtract the product from the dividend. 4. Divide the first term of this remainder by the first term of the divisor, obtaining the second term of the quotient. Multiply... | |
 | William James Milne - 1908 - 476 σελίδες
...root, and subtmct the product from the first remainder. Find the next term of the root by dividing the first term of the 'remainder by the first term of the trial divisor. Extract the square root of : 10. 25 a'2 - 40 a + 16. 13. 4 ж4 - 52 ^ + 169. 11. 900... | |
 | Jacob William Albert Young, Lambert Lincoln Jackson - 1909 - 292 σελίδες
...2b2 a- Multiply the entire divisor by a and 2 , T subtract, as in the case of numbers. Di_L O7)2 vide the first term of the remainder by the first term of the divisor again; the + ^ — quotient is 26. Multiply and subtract, as in the case of numbers. Test: Compare... | |
 | Herbert Edwin Hawkes, William Arthur Luby, Frank Charles Touton - 1910 - 374 σελίδες
...term of the quotient. to write the terms of the remainder in the same order as those of the divisor. Divide the first term of the remainder by the first term of the divisor for the second term of the quotient and proceed as before until there is no remainder, or until the... | |
 | Herbert Edwin Hawkes, William Arthur Luby, Frank Charles Touton - 1911 - 288 σελίδες
...subtract, being careful to write the terms of the remainder in the same order as those of the divisor. Divide the first term of the remainder by the first term of the divisor for the second term of the quotient, and proceed as before until there is no remainder, or until the... | |
 | William James Milne - 1911 - 378 σελίδες
...root, and subtract the product from the first remainder. Find the next term of the root by dividing the first term of the remainder by the first term of the trial divisor. 4a;2 4 ar + 3 x 4 ж2 + 6 x 4ж2 + 6ж-3 12 ж3 - 3 ж-' 12 ж3 + 9 ж2 -12Ж2 12 ж2... | |
 | Herbert Ellsworth Slaught, Nels Johann Lennes - 1912 - 306 σελίδες
...quotient is the first term of the quotient. 3. Multiply the first term of the quotient by the divisor and subtract the product from the dividend. 4. Divide the first term of this remainder by the first term of the divisor, obtaining the second term of the quotient. Multiply... | |
 | Webster Wells, Walter Wilson Hart - 1912 - 344 σελίδες
...subtract the result from the given expression. 3. Double the root already found, for the trial divisor. Divide the first term of the remainder by the first term of the trial divisor. Add the quotient to the root and also to the trial divisor, obtaining the complete divisor.... | |
 | Webster Wells, Walter Wilson Hart - 1912 - 504 σελίδες
...step 2. 5. Continue in this manner : (a) double the root already found for a new trial divisor ; (ft) divide the first term of the remainder by the first term of this product for the new term of the root ; (с) add the new term of the root to the trial divisor,... | |
 | Webster Wells, Walter Wilson Hart - 1912 - 344 σελίδες
...step 2. 5. Continue in this manner : (a) double the root already found for a new trial divisor ; (6) divide the first term of the remainder by the first term of this product for the new term of the root ; (c) add the new term of the root to the trial divisor,... | |
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