 | 1851 - 716 σελίδες
...this proposition is known as the Pythagorean : the square described upon the hypothenuse is equivalent to the sum of the squares described on the other two sides. As the unit of measure for the determination of the superficial relations of figures, we use a square... | |
 | Charles Davies - 1852 - 438 σελίδες
...worthy of particular notice. In every right angled triangle, the square described on the hypothenuse, is equal to the sum of the squares described on the other two sides. Thus, if ABC be a right angled tria,ngle, right angled at C, then will the square D described on AB... | |
 | Adrien Marie Legendre - 1852 - 436 σελίδες
...right-angled triangle, right-angled at A : then will the square described on the hypothenuse BC be equivalent to the sum of the squares described on the other two sides, BA, AC. FGI H D Haying described a square on each of the three sides, let fall from A, on the hypothenuse,... | |
 | Daniel Leach - 1853 - 622 σελίδες
...sides the base and perpendicular. 293. The square described on the hypothenuse, or longest side, is equal to the sum of the squares described on the other two sides. Thus, suppose the longest side is 10 ft., the base 6 ft., and the perpendicular 8 ft. 10a=100. 6a=36.... | |
 | John Smith (of Malton.) - 1854 - 334 σελίδες
...and habit will render it the most delightful." Ovidf represents him as arguing thus : * "The square on the hypothenuse of any right-angled triangle is equal to the sum of tho two squares on the base and perpendicular." t Metamorphoses, B. xv., 1. 101. " O mortals, from... | |
 | Thomas Fisher - 1854 - 156 σελίδες
...possibly be given of this invariable problem, that the square drawn upon the longest side, (that is the hypothenuse,) of any right-angled triangle is equal to the sum of the squares (which may be drawn) on the other two sides. The squares of the two sides are faintly drawn,... | |
 | Charles Davies - 1854 - 436 σελίδες
...triangle, right•angled at A : then will the square described on the hypothenuse BC be equivalent to the sum of the squares described on the other two sides, BA, AC. 1 GEOMETRY. Having described a square on each of the three sides, let fall from A, on the hy•... | |
 | James Bates Thomson - 1855 - 436 σελίδες
...AC, contain as many square feet as the square described on the hypothenuse BC. Now(4)2-|-(3)2=25sq. ft. ; and the square described on BC also contains 25 sq. ft. Hence, the square described on the hijpoLhenuse of any right-angled triangle, is equal to the sum of the squares described on the oilier... | |
 | James Stewart Eaton - 1857 - 376 σελίδες
...or circumferences. FIG. 12. 6. The square described on the hypothenuse of a right-angled triangle is equal to the sum of the squares described on the other two sides. This will be seen by counting the small squares in the square of the hypothenuse and those in the squares... | |
 | John Daniel Runkle - 1859 - 478 σελίδες
...BT JAMES IIIUVAIIII OLIVER. The square described on t/te hypothenusc of a right-angled triangle is equal to the sum of the squares described on the other two sides. Drop a perpendicular from the right angle to the hypothenuse, and prove in the usual way that the two... | |
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Now (4)2+(3)2=25 sq. ft. ; and the square described on BC also contains 25 sq. ft. Hence, the square described on the hypothenuse of any right-angled triangle, is equal to the sum of the squares described on the other two sides. 
