 | George Roberts Perkins - 1855 - 388 σελίδες
...COLUMN, for its next term. Multiply this term by the last found figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a NEW DIVIDEND. Proceed as before until all the periods have been brought down. NOTE 1.... | |
 | Benjamin Peirce - 1855 - 308 σελίδες
...of the divisor. Multiply the divisor, thus augmented, by the last figure of the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Double the root now found for a new divisor and continue the operation as... | |
 | Charles Davies, William Guy Peck - 1855 - 628 σελίδες
...divisor. IV. Multiply the divisor thus obtained by the last digit of the root found ; subtract ïhe product from the dividend, and to the remainder bring down the next period for a new dividend. If the product just found exceeds the dividend, diminish the last digit... | |
 | Joseph Ray - 1857 - 348 σελίδες
...part of the dividend from which it was obtained. 4 Subtract this product from the figures above it ; to the remainder bring down the next figure of the dividend, and divide as before, until all the figures of the dividend are brought down. 5. If, at any time, after... | |
 | James Stewart Eaton - 1857 - 376 σελίδες
...product, 12, under the 13 of the dividend and Subtract it therefrom. To the remainder, 1, we annex 8, the next figure of the dividend, and then inquire how many times the divisor is contained in 18, the second partial dividend; the result, 4, we set as the second figure... | |
 | Benjamin Greenleaf - 1857 - 452 σελίδες
...the same for a true divisor. Multiply the true divisor by the last figure of the root : subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. To the last true divisor and the number immediately over it, add the square... | |
 | Thomas William Silloway - 1858 - 236 σελίδες
...likewise on the right hand of the divisor. Multiply the divisor by the last quotient-figure, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, 4th, Double the quotient already found for a partial divisor, and from these... | |
 | Benjamin Greenleaf - 1858 - 472 σελίδες
...figure, for a true divisor. Multiply the true divisor by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Multiply the square of (lie root figures already found by 3, and to the... | |
 | Elias Loomis - 1858 - 394 σελίδες
...second figure. 5. Multiply the divisor thus increased by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 6. Take three hundred times the square of the whole root now found for a... | |
 | Horatio Nelson Robinson - 1859 - 362 σελίδες
...divisor, 23, by the quotient figure, 2, and subtract the product, 46, from the part of the dividend used, and to the remainder bring down the next figure of the dividend, which is 0, making 20, for the second partial dividend. Then, since 23 is contained in 20 no times,... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
