 | Horatio Nelson Robinson - 1860 - 444 σελίδες
...the complete divisor. V. Multiply the complete divisor by the trial figure ; subtract the. product from the dividend, and to the remainder bring down the next period for a new dividend. VI. Add the square of the last figure of the root, the last term in column II, and the complete divisor... | |
 | James Bates Thomson - 1860 - 440 σελίδες
...; multiply- the divisor thus completed by the figure last placed in the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. IV. Double the root already found for a new partial divisor, divide, <£c., as before, and thus continue... | |
 | Benjamin Greenleaf - 1860 - 456 σελίδες
...the true divisor, which multiply by the last root figure and subtract the product from the dividend. To the remainder bring down the next period for a new dividend. Double the root already found for a new trial divisor, and continue the operation as before, till all... | |
 | Charles Hutton - 1860 - 1020 σελίδες
...from that sum, setting do remainder, and carrying I, for what was borrowed, to the next lower figui which proceed as before, and so on till the whole is finished. TO PROVE SUBTRACTION. ADD the remainder to the less number, or that which is just above it, the sum... | |
 | Daniel Adams - 1861 - 452 σελίδες
...the root (the breadth of the additions), and subtract the contents of the additions thus obtained, from the dividend, and to the remainder bring down the next period for a new dividend. IV. Double the root already found for a new divisor, and continue the operation as before, until all... | |
 | Charles Davies - 1861 - 496 σελίδες
...divisor : IV. Multiply the divixor thus increased, by the last figure of the root j subtract the product from the dividend, and to the remainder bring down the next period for a new dividend: V. Double the whole root thus found, for a new trial divisor, -and continue the operation as before,... | |
 | Charles Davies - 1861 - 322 σελίδες
...divisor. IV. Multiply the divisor, thus augmented, by the lastfyurt of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. But if any of the products should be greater than the dividend, diminish the last figure of the root... | |
 | Benjamin Greenleaf - 1861 - 338 σελίδες
...figure last annexed by the figure annexed to the root. and subtract the product from the dividend. To the remainder bring down the next period for a new dividend. Double the root already found for a new divisor, and continue th*. operation as before, till all the... | |
 | James Bates Thomson - 1862 - 436 σελίδες
...; multiply the divisor thus completed by the figure last placed in the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. IV. Double the root already found for a new partial divisor, divide, &c., as before, and thus continue... | |
 | John Flint (inspector of schools.) - 1862 - 152 σελίδες
...divisor. Multiply the divisor thus completed by the figure of the root last found, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, and for a new divisor add the figure of the root last found, with which proceed as before, and continue... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
