In the multiplication of whole numbers, place the multiplier under the multiplicand, and multiply each term of the multiplicand by each term of the multiplier, writing the right-hand figure of each product obtained under the term of the multiplier which... The Elements of Algebra - Σελίδα 73των Elias Loomis - 1856 - 268 σελίδεςΠλήρης προβολή - Σχετικά με αυτό το βιβλίο
| William Frothingham Bradbury, Grenville C. Emery - 1894 - 144 σελίδες
...this equals Hence, for the multiplication of a polynomial by a polynomial, we have the following Bule. Multiply each term of the multiplicand by each term of the multiplier, and find the sum of the several products. 2. Multiply За2 — 2а6 + 462 by 2a — 3b. 3 a* — 2 а... | |
| William Frothingham Bradbury, Grenville C. Emery - 1894 - 166 σελίδες
...Hence, for the multiplication of a polynomial by a polynomial, we have the following Rule. Midtiply each term of the multiplicand by each term of the multiplier, and find the sum of the several products. 2. Multiply Зa2 — 2 a ¿ + 4 ¿2 by 2 a — 3 ¿. Зa2—... | |
| George Albert Wentworth - 1894 - 204 σελίδες
...+ bm + 6n + bp + cm -f- en + cp. To find the product of two polynomials, therefore, Multiply every term of the multiplicand by each term of the multiplier, and add the partial products. 88. In multiplying polynomials, it is a convenient arrangement to write the multiplier... | |
| George P. Lilley - 1894 - 522 σελίδες
...х - 25 z10 + 2 а? + 7 z6 - 8 х4 - 3 х8 - 15 ж8 + 10 хг - 5 а; -25 Explanation. Multiplying each term of the multiplicand by each term of the multiplier and connecting these results with their proper signs, we have x10 — x9 + 2 xe — x6 — 5 x* + 3 z9... | |
| George Washington Hull - 1895 - 358 σελίδες
...Adding the partial products, we 2a2 + ab - 662, Ans. have 2aJ + 06 - 66Z. From this example we derive the following RULE. Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. m2 + 2mn + w2, ^4ns. m2 — 2mn + n2 m'1 5. 6. a4 + rt'6 + a262 x*-x« + z4 -... | |
| Edward Brooks - 1895 - 424 σελίδες
...placing terms of the same order in the same column, and draw a line beneath. II. Begin at the right, and multiply each term of the multiplicand by each term of the multiplier, writing the first term of each product under the term of the multiplier used to obtain it. III. Add... | |
| Fletcher Durell, Edward Rutledge Robbins - 1897 - 482 σελίδες
...Polynomials. The Distributive Law applies here as in ordinary algebraic multiplication of polynomials; hence, Multiply each term of the multiplicand by each term of the multiplier ; Simplify each term of the result, and collect. Ex.1. Multiply 31/2 + 5 1/3 by 31/2-1/3: 31/2" + 51/3... | |
| 1897 - 358 σελίδες
...Ans. (14) In the multiplication of whole numbers, place the multiplier under the multiplicand, and multiply each term of the multiplicand by each term of the multiplier, writing the right-hand figure of each product obtained under the term of the multiplier which produces... | |
| Silas Ellsworth Coleman - 1897 - 180 σελίδες
...From this example we may deduce the following rule for the multiplication of algebraic quantities : Multiply each term of the multiplicand by each term of the multiplier. * This article may be omitted at the discretion of the teacher. When the two terms of a product have... | |
| George Egbert Fisher, Isaac Joachim Schwatt - 1898 - 712 σελίδες
...preceding article is derived the following principle for multiplying a multinomial by a multinomial: Multiply each term of the multiplicand by each term of the multiplier, and add algebraically the resulting products. Ex. l. Multiply -3a + 2& by 2a-36. We have -36x26 (1) = - 6 a2... | |
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