 | Horatio Nelson Robinson - 1846 - 276 σελίδες
...(2) r — 1 Equation (2), put in words, gives the following rule for the sum of a geometrical series: RULE. Multiply the last term by the ratio, and from the , product subtract the first term, and divide the remainder by the ratio less one. EXAMPLES FOR THE APPLICATION OP EQUATIONS (1) AND (2).... | |
 | George Roberts Perkins - 1846 - 266 σελίδες
...given the sum of all the terms, the last term, and the ratio, to find the first term, we have this RULE. Multiply the last term by the ratio, and from the product subtract the product of the sum of all the terms into the ratio, less one. EXAMPLES. 1. The sum of all the terms... | |
 | William Vogdes - 1847 - 324 σελίδες
...series. RULE. Multiply the last term by the ratio, and fioni the product subtract the first term ; the remainder divided by the ratio, less one, will give the sum of the series. EXAMPLES. 1. The first term of a series in geometrical progression is 1, the last term is 2187, and... | |
 | Horatio Nelson Robinson - 1848 - 354 σελίδες
...(Art. 116.) Equation (2), put in words, gives the following rule for the sum of a geometrical series ; RULE. Multiply the last term by the ratio, and from the product subtract the first term, and divide the remainder by the ratio less one. EXAMPLES FOR THE APPLICATION OF EQUATIONS (1) AND (2).... | |
 | George Roberts Perkins - 1849 - 356 σελίδες
...given the sum of all the terms, the last term, and the ratio, to find the first term, we have this RULE. Multiply the last term by the ratio, and from the product subtract the product of the sum of all the terms into the ratio, less one. EXAMPLES. 1. The sum of all the terms... | |
 | Uriah Parke - 1849 - 414 σελίδες
...of the series. This then is as many times the true sum, as the ratio less one, and being accordingly divided by the ratio less one, will give the sum of the series. Having therefore the first term, ratio, and number of terms, we can readily find the last term by involving... | |
 | Horatio Nelson Robinson - 1850 - 256 σελίδες
...simply equation ( 1 ) put in words. Equation (2) gives the following rule for the sum of a series. RULE . — Multiply the last term by the ratio, and from the product subtract the first term, and divide the remainder by the ratio less one. GENERAL EXAMPLES IN GEOMETRICAL PROGRESSION. 1. What is... | |
 | Charles Guilford Burnham - 1850 - 350 σελίδες
...term, last term, and ratio, are given, to find the sum of the series, we have the following l RULES. I. Multiply the last term by the ratio, and from the product subtract the first term, and divide the remainder by the ratio less 1; the quotient will be the answer. II. Divide the difference... | |
 | George Roberts Perkins - 1850 - 356 σελίδες
...given the sum of all the terms, the last term, and the ratio, to find the first term, we have this RULE. Multiply the last term by the ratio, and from the product subtract the product of the sum of all the terms into the ratio, Jess one. EXAMPLES. 1. The sum of all the terms... | |
 | Uriah Parke - 1850 - 402 σελίδες
...of the series. This then is as many times the true sum, as the ratio less one, and being accordingly divided by the ratio less one, will give the sum of the series. Having therefore the first term, ratio, and number of terms, we can readily find the last term by involving... | |
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The first term, the last term (or the extremes) and the ratio given, to find the sum of the series. RULE. Multiply the last term by the ratio, and from the product subtract the first term ; then divide the remainder by the ratio, less by 1, and the quotient... 
