 | James Morton - 1887 - 236 σελίδες
...right hand of the divisor and under the same, and multiply the divisor by this figure. Subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, and so continue until all the periods are brought down. Jf any dividend... | |
 | Horatio Nelson Robinson - 1888 - 372 σελίδες
...will be the complete divisor. V. Multiply the complete divisor by the trial figure, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. VI. Add the square of the last figure of the root, the last term in column... | |
 | Horatio Nelson Robinson - 1892 - 428 σελίδες
...a complete divisor; multiply the complete divisor by the trial figure in the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. To the last complete divisor add the last figure of the root, and to... | |
 | Frank Eugene Kidder - 1892 - 1058 σελίδες
...the divisor, multiply this final divisor by the number in the quotient just found, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, and proceed as before. 1f it should be found that the trial divisor cannot... | |
 | Horatio Nelson Robinson - 1892 - 428 σελίδες
...a complete divisor; multiply the complete divisor by the trial figure in the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. To the last complete divisor add the last figure of the root, and to... | |
 | Henry Bartlett Maglathlin - 1893 - 234 σελίδες
...dividend. Multiply the divisor hy this quotient; subtract the product from the part of the dividend used, and to the remainder bring down the next figure of the dividend. Divide as bef ore, and so continue till all the figures of the dividend have been used. If there lie... | |
 | Henry B. Maglathlin - 1894 - 370 σελίδες
...dividend. Multiply the divisor by this quotient; subtract the product from, the part of the dividend used, and to the remainder bring down the next figure of the dividend. Divide as before, till all the figures of the dividend have been used. If there be a final remainder,... | |
 | Thomas Rhys Vickroy - 1895 - 174 σελίδες
...Multiply the divisor by the number thus found and subtract its product from the orders divided. 4. To the remainder bring down the next figure of the dividend and proceed as in 2. 6. Write the final remainder over the divisor at the right of the quotient. Caution... | |
 | Horatio Nelson Robinson - 1895 - 526 σελίδες
...a complete divisor ; multiply the complete divisor by the trial term in the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. To the last complete divisor add the last term of the root, and to the... | |
 | William Frothingham Bradbury - 1895 - 398 σελίδες
...product, 23, under the 28 of the dividend, and subtract it therefrom. To the remainder, 5, we annex 7, the next figure of the dividend, and then inquire how many times the divisor is contained in 57, the second partial dividend ; the result, 2, we write as the second... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
