 | Nathan Daboll - 1825 - 248 σελίδες
...second term to the lowest name mentioned in it. 3. Multiply the second and third terms together, and j divide their product by the first term ; the quotient...may be brought into any other denomination required. V The method of proof is by inverting the question. NOTE. — The following methods of operation, when... | |
 | John White - 1826 - 128 σελίδες
...first and third terms into the same denomination, and the second into the lowest name mentioned. 2. Multiply the second and third terms together, and divide their product by the first, and their quotient will be the answer, in the same denomination as that in which the second was left.... | |
 | John Dozell - 1827 - 190 σελίδες
...term mentioned. Multiply the second and third numbers together, and divide the product by the first, the quotient will be the answer to the question in the same denomination as you left the second number in. If there happen to be a remainder after the Division, reduce it into... | |
 | Martin Ruter - 1828 - 180 σελίδες
...Reduce, likewise, the first and second terms to the lowest denomination that either of them has. Then multiply the second and third terms together, and...divide their product by the first term. The quotient thus obtained will be the answer. It will not be necessary to distinguish between direct and inverse... | |
 | William Slocomb - 1828 - 160 σελίδες
...first and third terms to the same denomination, and the second to the lowest name mentioned in it. e 3. Multiply the second and third terms together, and divide their product by the first; the quotient will be the answer to the question, in the same denomination in which you left the second... | |
 | Roswell Chamberlain Smith - 1829 - 284 σελίδες
...it to the lowest denomination mentioned, by Reduction. VI. How do you proceed in the operation ? A. Multiply the second and third terms together, and...product by the first term ; the quotient will be the fourth term, or answer, in the same denomination with the third term. VII. How may this process of... | |
 | Roswell Chamberlain Smith - 1830 - 286 σελίδες
...it to the lowest denomination mentioned, by Reduction. VI. How do you proceed in the operation ? A. Multiply the second and third terms together, and...product by the first term ; the quotient will be the fourth term, or answer, in the same denomination with the third term. VII . How may this process of... | |
 | Thomas Smith (of Liverpool.) - 1830 - 282 σελίδες
...all the terms together that are not marked, and to divide the product by those that are marked ," and the quotient will be the answer to the question, in the same denomination as that in which you left the second term." Precepts without examples, are of little avail, whether... | |
 | Nathan Daboll - 1831 - 246 σελίδες
...and third terms tofrettier, and divide their product by tho first term ; and ilie quotient will iie the answer to the question, in the same denomination...second term in, which may be brought into any other denommation required. The method of proof is by inverting the question. [NOTE. — The lullon iny metuods... | |
 | Martin Ruter - 1831 - 190 σελίδες
...Reduce, likewise, the first and second terms to the lowest denomination that either of them has. Then multiply the second and third terms together, and...divide their product by the first term. The quotient thus obtained will be the answer. It will not be necessary to distinguish between direct and inverse... | |
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Multiply the second and third terms together, and divide their product by the first term ; the quotient will be the answer to the question, in the same denomination you left the second term in, which may be brought into any other denomination required. 
