 | Janet Taylor - 1851 - 674 σελίδες
...DIVISION OF DECIMALS. Divide as in whole numbers, observing to point off as many decimal places in the quotient, as the decimal places in the dividend exceed those in the divisor. If there be not as many figures in the quotient as are equal to that excess, supply the deficiency... | |
 | John Bonnycastle - 1851 - 314 σελίδες
...in whole numbers, and point off, from the right-hand of the quotient, as many places for decimals, as the decimal places in the dividend exceed those in the divisor ; observing, if there be not so many as the rule requires, to supply the defect by prefixing ciphers.... | |
 | Daniel Leach - 1851 - 280 σελίδες
...Divide as in whole . numbers, and point off from the right of the quotient as many figures for decimals as the decimal places in the dividend exceed those in the divisor ; and if there be not as many, make the number equal by prefixing ciphers to the quotient. PROOF. Division... | |
 | Oliver Byrne - 1851 - 310 σελίδες
...DECIMALS. RULE. — Divide as in whole numbers ; and point off in the quotient as many places for decimals, as the decimal places in the dividend exceed those in the divisor. . When the places of the quotient are not so many as the rule requires, let the defect be supplied... | |
 | Joseph Bateman - 1852 - 376 σελίδες
...these partial products point off the assigned number DECIMAL AND MENTAL ARITHMETIC. [CHAP. I. decimals as the decimal places in the dividend exceed those in the divisor ; or in other words to sce that the divisor and of decimal places. The example in the margin, which... | |
 | Daniel Leach - 1853 - 622 σελίδες
...Divide as in whole numbers, and point off from the right of the quotient as many figures for decimals as the decimal places in the dividend exceed those in the divisor ; and if there be not as many, make the number equal by prefixing ciphers to the quotient. PROOF. Division... | |
 | Charles Haynes Haswell - 1853 - 318 σελίδες
...DECIMALS. RULE. — Divide as in whole numbers, and point off in the quotient as many places for decimals as the decimal places in the dividend exceed those in the divisor ; but if there are not so many places, supply the deficiency by prefixing ciphers. EXAMPLE.— Divide... | |
 | Charles D. Lawrence - 1854 - 336 σελίδες
...Divide as in whole numbers ; and point off from the right hand of the quotient as many decimal places, as the decimal places in the dividend exceed those in the divisor. When the number of figures in the quotient is less than the number of decimal placet! in the dividend,... | |
 | Andrew Carrick (accountant.) - 1856 - 34 σελίδες
...Divide as in whole numbers, and for decimals, from the right of the quotient, point off as та' figures as the decimal places in the dividend exceed those in the divisor ; when there are not so many figures i quotient, supply the defect by prefixing ciphers ; or, 18 DECIMAI.... | |
 | Joseph Ray - 1857 - 348 σελίδες
...there are decimals in both divisor and quotient. Art. 181 : hence, There must be as many decimals in the quotient as the decimal places in the dividend exceed those in the divisor. 1. Divide 2.125 by 5 tenths. SOLUTION.— Divide as in Simple Numbers; KXO^O"*' then, since there are... | |
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RULE. Divide as in whole numbers, and from the right hand of the quotient point off as many places for decimals as the decimal places in the dividend exceed those in the divisor. 
