 | James Bates Thomson - 1844 - 272 σελίδες
...term in the given series. 373. To find the sum of a geometrical series. Multiply the last term into the ratio, from the product subtract the first term, and divide the remainder by the ratio less one. Obser. From the above formula, in connexion with the one in Art. 368, there may be the same variety... | |
 | George Hutton (arithmetic master, King's coll. sch.) - 1844 - 276 σελίδες
...of the given series, as the ratio less 1 is greater than 1. . , 3. Consequently, if we divide this remainder by the ratio less 1, the quotient will be the sum of the given series ; as will be manifest in the following example. Ex.—To find the sum of the series 5:15:... | |
 | James Bates Thomson - 1844 - 272 σελίδες
...series. 373. To find the sum of a geometrical series. Multiply the last term into the ratio, from {he product subtract the first term, and divide the remainder by the ratio less one. Obter. From the above formula, in connexion with the one in Art. 368, there may be the same variety... | |
 | 1845 - 196 σελίδες
...terms given, which, being multiplied by the first term, will give the last term, or greater extreme. 2. Multiply the last term by the ratio, from the product...subtract the first term, and divide the remainder by ratio less one for the sum of the series. EXAMPLES. 1. A thresher wrought 20 days, and received for... | |
 | Horatio Nelson Robinson - 1846 - 276 σελίδες
...following rule for the sum of a geometrical series: RULE. Multiply the last term by the ratio, and from the , product subtract the first term, and divide the remainder by the ratio less one. EXAMPLES FOR THE APPLICATION OP EQUATIONS (1) AND (2). 1. Required the sum of 9 terms of the series,... | |
 | Elias Loomis - 1846 - 380 σελίδες
...Hence, to find the sum of the terrns of a geometrical progression, Multiply the last term by the ratio, subtract the first term, and divide the remainder by the ratio less one. If a series is a decreasing one, andr consequently represents a fraction, it is convenient to... | |
 | Almon Ticknor - 1846 - 276 σελίδες
...is the last term, or greater extreme. . 2. Multiply the last term by the ratio, and from the prodiut subtract the first term, and divide the remainder by the ratio ^ less one ; the quotient will be the sum of the series. Or, raise the ratio to a power equal to the number... | |
 | Elias Loomis - 1846 - 376 σελίδες
...I already found, we obtain Ir — a ~ r — 1 ' PROGRESSIONS. Multiply the last term by the ratio, subtract the first term, and divide the remainder by the ratio less one. If a series is a decreasing one, and r consequently represents a fraction, it is convenient to... | |
 | Roswell Chamberlain Smith - 1847 - 308 σελίδες
...Wlien the Extremes and Ratio are given, to find the Sum of (he Series, we have tlie following easy RULE. Multiply the last term by the ratio, from the...quotient will be the sum of the series required. 9. If tbe extremes be 5 and 6400, and the ratio 6, what is the whole amount of tbe series 1 6400X6 — 5... | |
 | James Robinson (of Boston.) - 1847 - 304 σελίδες
...rule in Art. 179, then multiply the last term by the ratio, subtract the first term from the product, and divide the remainder by the ratio, less 1 ; the quotient will be the sum of all the terms. 1. If the first term of a geometrical series be 2, and the ratio 3, what is the 4th... | |
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Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by the ratio, less 1; the quotient will be the sum of the series required. 
