 | Roswell Chamberlain Smith - 1830 - 286 σελίδες
...we have the following easy HULE. Multiply the last term by the ratio' from the product subtract t he first term, and divide the remainder by the ratio, less 1 ; the quotient will Ite the sum of the scries required^ 9. If the extremes be 5 and 6 Ю3, and the ratio 6, what is the... | |
 | Thomas Tucker Smiley - 1830 - 188 σελίδες
...term, and that product will be the last term. 3. Multiply the last term by the ratio; from the pro duct subtract the first term, and divide the remainder by the ratio, less 1, for the sum of the series. Questions. What is Geometrical Progression? What is the ratio ? By what... | |
 | Roswell Chamberlain Smith - 1831 - 286 σελίδες
...when the extremes and ratio are given, to find the sum of the series, we have the following easy HULE. Multiply the last term by the ratio, from the product...the quotient will be the sum of the series required. ft If the extremes be 5 and 6400, and the ratio 6, what Is the whole amount of the seciei.' i 10. A... | |
 | Charles Potts - 1835 - 202 σελίδες
...lessll than the number of terms given, and multiply it by the first | term, will give the last term. 2. Multiply the last term by the ratio, from the product...term, and divide the remainder by the ratio less 1, for the sum of the series. EXAMPLES. 1. A labourer wrought 20 days, and received for the first day's... | |
 | Stephen Pike - 1835 - 210 σελίδες
...terms given, which, being multiplied by the first term, will give the last term, or greater extreme. 2. Multiply the last term by the ratio, from the product...subtract the first term, and divide the remainder by ratio less one for the sum of the series. . EXAMPLES. 1. A thresher wrought 20 days, and received for... | |
 | A. Turnbull - 1836 - 368 σελίδες
...extending the series to one more than the given term, and from the last term of the series thus extended, subtract the first term, and divide the remainder by the ratio, less 1. The reason for this rule may be explained thus : * = 8 + 24 + 72 + 216 + 648 + 1944. . If we multiply the... | |
 | Roswell Chamberlain Smith - 1837 - 306 σελίδες
...Hence, When the Extremes and Ratio are ^iven, to fiad tbr Sum of the Series, we have thefottounng easy RULE. Multiply the last term by the ratio, from the...remainder by the ratio, less 1 ; the quotient will he the sum of the series required. 9. If the extremes be 5 and 6400, and the ratio 6, what is the whole... | |
 | 1838 - 218 σελίδες
...last ? Ans. $171798691,84. CASE 2. The extremes and ratio being given, to find the sum of the series. RULE. — Multiply the last term by the ratio, from...first term, and divide the remainder by the ratio less I, the quotient will be the sum of the series. The reason of the rule may be shown in the following... | |
 | Nathan Daboll - 1839 - 220 σελίδες
...The first term, the last term, (or the extremes,) and the ratio given, to find the sum of the series. RULE. Multiply the last term by the ratio ; from the...first term, and divide the remainder by the ratio, loss 1, and the quotient will be the sum of all the terms. EXAMPLES. 1. A man bought 6 yards of cloth,... | |
 | Jason M. Mahan - 1839 - 312 σελίδες
...of the ratio as is indicated by the number of terms less one, and the product will be the last term. Multiply the last term by the ratio, from the product...first term, and divide the remainder by the ratio less one ; the quotient will be the sum of the series. Examples. 123 4 indices. 6 36 216 1296 leading terms.... | |
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Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by the ratio, less 1; the quotient will be the sum of the series required. 
