 | Charles Davies - 1833 - 284 σελίδες
...IV. Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Double the whole root already found, for a new divisor, and continue the operation as before, until... | |
 | Frederick Emerson - 1834 - 300 σελίδες
...Multiply the divisor thus completed, by the figure last placed in the root, and subtract the product from the dividend; and to the remainder bring down the next period for a new dividend. Thus proceed, till the whole root is extracted. Observe, that, when the divisor is not contained in... | |
 | Charles Davies - 1835 - 378 σελίδες
...IV. Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Double the whole root already found, for a new divisor, and continue the operation as before, until... | |
 | James L. Connolly (mathematician.) - 1835 - 264 σελίδες
...adding thereto SO times the product of the last figure of the root into the rest. Multiply, subtract, and to the remainder bring down the next period for a new resolvend : add together the last complete divisor, the number that completed it, and twice the square... | |
 | Charles Guilford Burnham - 1837 - 266 σελίδες
...the last ; under these write the cube of the last quotient figure, and call their sum the subtrahend. Subtract the subtrahend from the dividend, and to...remainder bring down the next period, for a new dividend, and proceed as before, till the work is finished. EXAMPLES. 2. What is the cube root of 1906624 ? Operation.... | |
 | Benjamin Peirce - 1837 - 300 σελίδες
...divisor. Multiply the divisor, thus augmented, by the last figure of the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Double the root now found for a new divisor and continue the operation as before, until all the periods... | |
 | Benjamin Peirce - 1837 - 302 σελίδες
...divisor. Multiply the divisor, thus augmented, by the last figure of the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Double the root now found for a new divisor and continue the operation as before, until all the periods... | |
 | Peirpont Edward Bates Botham - 1837 - 252 σελίδες
...partial subtrahend, which parts add together, calling their amount the total subtrahend. 5. Subtract said subtrahend from the dividend, and to the remainder bring down the next period, for another dividend. 6. To find a divisor for said dividend, square the figures in the quotient, and multiply... | |
 | Luther Ainsworth - 1837 - 298 σελίδες
...figure of the root ; then place the square of it under the first period, and subtract it therefrom, and to the remainder bring down the next period, for a new dividend. Q. You have now found the first figure of the root ; what is the next process ? A. Double this first... | |
 | 1838 - 372 σελίδες
...IV. Multiply the divisor, thus augmented, by the last figure of tht, root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Double the whole root already found, for a new divisor, and continue the operation as before, until... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
