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Multiply all the numerators together for a new numerator, and all the denominators for a new denominator: then reduce the new fraction to its lowest terms.
The North American Arithmetic: Part Second, Uniting Oral and Written ... - Σελίδα 171
των Frederick Emerson - 1854 - 216 σελίδες
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## The United States Arithmetic: Designed for Academies and Schools

William Vogdes - 1847 - 256 σελίδες
...fraction whose denominator shall be 90. § 71. CASE 5. To reduce compound to simple fractions. RULE. Multiply all the numerators together for a new numerator, and all the denominators for a new denominator, and they will form the simple fraction required; which should then be reduced...

## Elements of Algebra: Being an Abridgment of Day's Algebra, Adapted to the ...

Jeremiah Day, James Bates Thomson - 1848 - 252 σελίδες
...— - - =. 29. Reduce b — -. - . 1 A— d d—y 121. To reduce a compound fraction to a simple one. Multiply all the numerators together for a new numerator and all the denominators for a new denominator. 2a 30. Reduce _ of . Ans. 7 6+2 76+14 31. Reduce ? of * of 6+A . 32. Reduce...

## An Arithmetical Dictionary: Or Book of Reference: Comprising a System of ...

William B. Young - 1848 - 297 σελίδες
...一 " 16 th 笛 eExamplesandthepre 忱 d @ ng , RULE.@To Reduce a Compound Fraction to a single one, Multiply all the Numerators together for a new Numerator, and all the Denominators, for a new Denominatpr, which reduce, if necessary, to their lowest Terms. What 油 芸 of ; of 各...

## Higher Arithmetic, Or, The Science and Application of Numbers: Combining the ...

James Bates Thomson - 1848 - 422 σελίδες
...numerators together and the two denominators. Hence, 198. To reduce compound fractions to simple ones. Multiply all the numerators together for a new numerator, and all the denominators together for anew denominator. OBS. 1. That a compound fraction may be expressed by a simple one, is...

## The Elements of Arithmetic...: In which Decimal and Integral ..., Μέρος 2

Pliny Earle Chase - 1848 - 240 σελίδες
...Thus, since 2=ff , 2T5T=fy + T5T= TTA compound fraction may be reduced to a simple one, by multiplying all the numerators together for a new numerator, and all the denominators for a new denominator. Thus, | of |=^| . For|of J=3*j. because, if we suppose a unit divided into 6...

## American Common-school Arithmetic ...

Rufus Putnam - 1849
...fractional form; and, after cancelling the factors which are common to the numerator and denominator, multiply all the numerators together, for a new numerator, and all the denominators, for a new denominator. 1. Reduce the following compound fractions io simple ones. * of ¿ of|; f of...

## Scribner's Engineers' and Mechanics' Companion: Comprising United States ...

J. M. Scribner - 1849 - 264 σελίδες
...MULTIPLICATION OF VULGAR FRACTIONS. Rule. — Prepare the fractions, as previously required ; then multiply all the numerators together for a new numerator, and all the denominators for a new- denominator. Examples. — 1. Multiply J of 7 by £ f of 7= j' and V x|=f\$=4}. Ans. 2. What...

## Higher Arithmetic: Designed for the Use of High Schools, Academies, and ...

George Roberts Perkins - 1849 - 342 σελίδες
...the word OF, which connects the fractional parts as equivalent to the sign of multiplication. Then multiply all the numerators together for a new numerator, and all the denominators together for a new denominator, always observing to reject or cancel such factors as are common to...

## An Elemtary Arithmetic ...: Serving as an Introduction to the Higher ...

George Roberts Perkins - 1849 - 347 σελίδες
...same rule as for reducing compound fractions. Therefore, to multiply fractions, we have this RULE. Multiply all the numerators together for a new numerator, and all the denominators together for a new denominator ; always observing to reject or cancel such factors as are common to...

## Daboll's Complete Schoolmaster's Assistant: Being a Plain Comprehensive ...

Nathan Daboll, David Austin Daboll - 1849 - 249 σελίδες
...equal parts, it will take 12 such parts to make a whole one ; therefore ^ of -J- is iJj, Answer: RULE. Multiply all the numerators together for a new numerator, and all the denominators for a new denominator, and they will form the fraction required, which reduce to its lowest terms....