 | James Bates Thomson - 1848 - 434 σελίδες
...must cost f of $ of a dollar. Now -^ of 1 is a compound fraction, whose value is found by multiplying the numerators together for a new numerator, and the denominators for a new denominator. (Art. 198.) Solution. — lX^—i^, or -fo dollars, Ans. Hence, 219. To multiply a fraction by a fraction.... | |
 | Horatio Nelson Robinson - 1866 - 328 σελίδες
...given denominators. Hence, the RULE. I. Reduce entire and mixed quantities to fractional forms. II. Multiply the numerators together for a new numerator, and the denominators, for a new denominator, canceling all factors common to the numerator and denominator of the indicated product. EXAMPLES FOR... | |
 | Horatio Nelson Robinson - 1866 - 200 σελίδες
...have T62=2 for the required product Hence we have the following RULE. Multiply together the numerators for a new numerator, and the denominators for a new denominator, and reduce the result to its lowest terms. EXAMPLES FOR PRACTICE. 6. Multiply I by f . Ans. " 7. Multiply | by f Ana.... | |
 | George Payn Quackenbos - 1867 - 148 σελίδες
...or to reduce a compound fraction, first cancel factors common to any numerator and denominator; then multiply the numerators together for a new numerator, and the denominators for a new denominator. 2. Whole numbers occurring in a compound fraction must first be reduced to a fractional form, and mixed... | |
 | James Bates Thomson - 1867 - 204 σελίδες
...bushel must be worth 1 third of 3 fourths of a dollar, which is &J-. Therefore, &c. Or, multiplying the numerators together for a new numerator, and the denominators for a new denominator, &j Xi=$A, or $i. 14. What is £ off? £off ? 15. A boy having j- of a watermelon, gave away -J of what... | |
 | Richard Nelson - 1867 - 304 σελίδες
...| [Note 1, page 82.] . 79. Hence, to multiply a fraction by a fraction, we multiply the numeratort together for a new numerator, and the denominators for a new denominator. ^X«=jf, which, reduced to its lowest terms=|.* *It will be observed that to multiply by a fraction... | |
 | Joseph Ray - 1857 - 358 σελίδες
...of ribbon can be purchased for | of a dollar? Ans. 3|. Rule for Case III. — Invert the divisor ; multiply the numerators together for a new numerator, and the denominators for a new denominator. NOTE. — Reduce compound to simple fractions, and mixed numbers to improper fractions, before commencing... | |
 | William Frothingham Bradbury - 1868 - 270 σελίδες
...and -5- -^- y = •=— (Art. 93) must be — -~- y = j— b by^ y the product sought. Hence, RULE. Multiply the numerators together for a new numerator, and the denominators for a new denominator. NOTE 1. — Common factors in the numerators and denominators may be cancelled before multiplication.... | |
 | Elias Loomis - 1868 - 386 σελίδες
...according to the second principle of Art. 109, we obtain Hence we have the following ac _ aa RULE. Multiply the numerators together for a new numerator, and the denominators for a new denominator. Entire and mixed quantities should first be reduced to fractional forms. Also, if there are any factors... | |
 | Horatio Nelson Robinson - 1868 - 430 σελίδες
...denominators. Hence the following RULE. I. Reduce entire and mixed quantities to fractional forms. II. Multiply the numerators together for a new numerator, and the denominators for a new denominator, canceling аи factors common to the numerator and denominator of the indicated product. .EXAMPLES... | |
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Reduce compound fractions to simple ones, and mixt numbers to improper fractions ; then multiply the numerators together for a new numerator, and the denominators for. a new denominator. 
