 | Frederick Emerson - 1835 - 300 σελίδες
...completed. Lastly — Multiply the divisor thus completed, by the figure last placed in the root, and subtract the product from the dividend; and to the remainder bring down tht next period for a new dividend. Thus proceed, till the whole root is extracted. Observe, that,... | |
 | James L. Connolly (mathematician.) - 1835 - 264 σελίδες
...adding thereto SO times the product of the last figure of the root into the rest. Multiply, subtract, and to the remainder bring down the next period for a new resolvend : add together the last complete divisor, the number that completed it, and twice the square... | |
 | Benjamin Snowden - 1835 - 108 σελίδες
...greater than the dividend, put a less figure than the last to the root, and alter the work. 8. — To the remainder bring down the next period for a new dividend, with which proceed as with the first dividend, until all the periods are brought down. Prove the work... | |
 | Lyman Cobb - 1836 - 228 σελίδες
...write the cube of this quotient figure, and call the amount the subtrahend. 1. Substract the subtrahend from the dividend, and to the remainder bring down the next period for a new dividend, with which proceed as before ; and so on, till the whole is finished. NOTE. — If the divisor can... | |
 | 1836 - 488 σελίδες
...and add these three results together for a subtrahend. 4. Subtract the subtrahend from the dividend, to the remainder bring down the next period for a new dividend, and so proceed. Arithmetical and Geometrical Progression. Any rank of numbers more than two, increasing... | |
 | Benjamin Peirce - 1837 - 302 σελίδες
...which figure is also to be placed at the right of the divisor. Multiply the divisor, thus augmented, by the last figure of the root, subtract the product...remainder bring down the next period for a new dividend. Double the root now found for a new divisor and continue the operation as before, until all the periods... | |
 | Benjamin Peirce - 1837 - 300 σελίδες
...which figure is also to be placed at the right of the divisor. Multiply the divisor, thus augmented, by the last figure of the root, subtract the product...remainder bring down the next period for a new dividend. Double the root now found for a new divisor and continue the operation as before, until all the periods... | |
 | Charles Guilford Burnham - 1837 - 266 σελίδες
...write the cube of the last quotient figure, and call their sum the subtrahend. Subtract the subtrahend from the dividend, and to the remainder bring down the next period, for a new dividend, and proceed as before, till the work is finished. EXAMPLES. 2. What is the cube root of 1906624 ? Operation.... | |
 | Peirpont Edward Bates Botham - 1837 - 252 σελίδες
...subtrahend, which parts add together, calling their amount the total subtrahend. 5. Subtract said subtrahend from the dividend, and to the remainder bring down the next period, for another dividend. 6. To find a divisor for said dividend, square the figures in the quotient, and multiply... | |
 | Shelton Palmer Sanford - 1872 - 404 σελίδες
...right of the trial divisor, to form tlie TRUE DIVISOR. IV. Multiply the TRUE DIVISOR by the second figure of the root, subtract the product from the...remainder bring down the next period for a new dividend. V. Double the root already found for a NEW TRIAL DIVISOE, 5625(75 An, 49 145)725 725 continue tlie... | |
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Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
