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" ... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained... "
Easy Introduction to Mathematics - Σελίδα 252
των Charles Butler - 1814
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Arithmetic Simplified in Three Parts

Catharine Esther Beecher - 1833 - 296 σελίδες
...greatest cube in the left hand period, and subtract it from that period. Place the root in the quotient, and to the remainder bring down the next period, for a dividend. 3. Square the root already found (understanding a cipher at the right) and multiply it by 3 for a divisor....

Adam's New Arithmetic: Arithmetic, in which the Principles of Operating by ...

Daniel Adams - 1833 - 268 σελίδες
...and write its root as a quotient in division. Subtract the square number.from the left hand period, and to the remainder bring down the next period for a dividend. . III. Double the root already found for a divisor ; seek how many times the divisor is contained in...

The millwright & engineer's pocket companion

William Templeton (engineer.) - 1833 - 224 σελίδες
...period ; then from the first period subtract the greatest cube it contains ; put the root as a quotient, and to the remainder bring down the next period for a dividend. Find a divisor by multiplying the square of the root by 300 ; see how often it is contained in the...

The North American Arithmetic: Part Third, for Advanced Scholars, Τόμος 3

Frederick Emerson - 1834 - 300 σελίδες
...period, and write its root in the quotient. Subtract the square of this root from the left hand period, and to the remainder bring- down the next period for a dividend. Thirdly — Double the root already found, for a divisor. Ascertain how many times the divisor is contained...

A brief compendium of arithmetic

Benjamin Snowden - 1835 - 108 σελίδες
...its root for the first figure of the root sought. 2. — Subtract this cube from the first period, and to the remainder bring down the next period for a dividend. 3. — Find a divisor by multiplying the square of the root by 300. 4. — Divide the dividend by this...

A New Introduction to the Science of Algebra ...

Silas Totten - 1836 - 332 σελίδες
...right, after the manner of a quotient in division. Subtract its cube from the aforementioned period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by 300, for a divisor. Seek how often the divisor is...

A Practical and Theoretical System of Arithmetic...: Also, a Treatise on ...

George Willson - 1836 - 202 σελίδες
...for the first figure of the root, and the square itself under the period, and subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Double the root already found, and annex a cipher to tho product, for a divisior. Seek how many...

The Teacher's Assistant in the "Course of Mathematics Adapted to the Method ...

1836 - 488 σελίδες
...subtract from the highest period the greatest square contained in it, place the root in the quotient, and to the remainder bring down the next period for a dividend. 2. Double the root already found, (understanding a cypher at the right,) for a divisor, and divide...

A New System of Arithmetic, on the Cancelling Plan: Embracing the Rules of ...

Charles Guilford Burnham - 1837 - 266 σελίδες
...quotient in division. Place the square of the root found, under said period, and subtract it therefrom, and to the remainder bring down the next period for a dividend. III. Double the root already found, for a divisor ; see how often the divisor is contained in the dividend,...

Practical Mercantile Arithmetic: In which the Theory and Practice of ...

Luther Ainsworth - 1837 - 298 σελίδες
...for the first figure of the root, and place the cube under the first period, subtract it therefrom, and to the remainder, bring down the next period for a dividend. Q. You have now found one figure of the root, what is your next process ? A. Multiply the square of...




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