 | Joseph Ray - 1852 - 408 σελίδες
...have +ar"~'+ar". This formula gives the following RULE, FOR FINDING THE SUM OF A GEOMETRICAL SERIES. Multiply the last term by the ratio, from the product subtract the first term,and divide the remainder by the ratio.less one. Ex. Find the sum of 6 terms of the progression... | |
 | Thomas Tucker Smiley - 1854 - 192 σελίδες
...last term. 1. Raise the ratio to the power whose index is one less than the number of terms given. 3. Multiply the last term by the ratio; from the product...first term, and divide the remainder by the ratio, less 1, for the sum of the series. Questions. What is Geometrical Progression? What is the ratio ?... | |
 | William Somerville Orr - 1854 - 534 σελίδες
...О rl- a r- 1 (1), and this formula, expressed in words, furnishes the following rule :— BULE. — Multiply the last term by the ratio ; from the product...first term, and divide the remainder by the ratio minus 1. This rule applies, of course, whether the ratio be whole or fractional, positive or negative.... | |
 | John Radford Young - 1855 - 218 σελίδες
...expressed in words, is the rule following, namely : — RULE. Multiply the last term by the common ratio ; from the product subtract the first term, and divide the remainder by the latio minus 1. The last term is the first multiplied as often by the ratio as there are terms following... | |
 | John Fair Stoddard - 1856 - 312 σελίδες
...ratio times 32 — 2. Therefore, the sum of the series equals 4 times 32 — 2-f-(4 — 1.) Hence, Multiply the last term by the ratio ; from the product...subtract the first term and divide the remainder by the raii^ diminished by one, and it will give the sum of all the terms. _ • 2. A gentleman engaged a... | |
 | Joseph Ray - 1857 - 408 σελίδες
...— 1 ' — 1 This formula gives the following RULE, FOR FINDING THE SUM OF A GEOMETRICAL SERIES. — Multiply the last term by the ratio, from the product subtract the first term,and divide the remainder by the ratio less one. Ex. Find the sum of 6 terms of the progression... | |
 | Joseph Ray - 1866 - 252 σελίδες
...H'ow may the common ratio in any geometrical series be found? TO FIND THE SUM OF A GEOMETRICAL SERIES, Rule. — Multiply the last term by the ratio, from...first term, and divide the remainder by the ratio less one. 1. Find the sum of 10 terms of the progression 2, 6, 18, 54, etc. The last term =2X3' =2... | |
 | Joseph Ray - 1866 - 420 σελίδες
...— a Therefore ...... 8= - =- = - =-. Hence, Rule for finding the Sum of a Geometrical Series. — Multiply the last term by the ratio, from the product...first term, and divide the remainder by the ratio less one. Find the sum of 6 terms of the progression 3, 12, 48, etc. 3=4095, Ans. order that both terms... | |
 | William Frothingham Bradbury - 1868 - 264 σελίδες
......... -f' + Zr(2) Subtracting (1) from (2), rS — S = I r — a lr _ a Whence, S= - — . Hence, RULE. ' Multiply the last term by the ratio, from...first term, and divide the remainder by the ratio less one. 1. Given a = 2, I= 20000, and r = 10, to find S. lr — a _ 20000 X 10 — 2 _ gf>p . S —... | |
 | William Frothingham Bradbury - 1868 - 270 σελίδες
...-{- -|-Z-|-Zr (3) Subtracting (1) from (2), r S — S = / r — a Whence, S = — -p. Hence, T ^~~~ 1 RULE. Multiply the last term by the ratio, from the product subtract the first term, and divide tlie remainder by the ratio less one. 1. Given a = 2, 1= 20000, and r = 10, to find S. *=£=£ = soooo^io... | |
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Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by the ratio, less 1; the quotient will be the sum of the series required. 
