 | Charles WATERHOUSE - 1844 - 228 σελίδες
...the difference of the extremes by the number of terms less 1, the quotient will be the difference. Multiply the sum of the extremes by the number of terms, and half the product will be the sum of all the terms. Qtitf lions. — What is Arithmetical Progression? — When are numbers an ascending... | |
 | Benjamin Greenleaf - 1845 - 334 σελίδες
...the last term, and the number of terms given to find the sum of all the terms. RULE. Multiply tint sum of the extremes by the number of terms, and half the product will be the sum. 5. The extremes of 'an arithmetical series are 3 and 45, and the number of terms 22. Required... | |
 | 1845 - 196 σελίδες
...difference, and to the product add the first term, the sum is the last term. 2. Multiply the sum of the two extremes by the number of terms, and half the product will be the sum of all the terms. EXAMPLES. 1 . The first term of a certain series in arithmetical progression... | |
 | Almon Ticknor - 1846 - 276 σελίδες
...term, the last term, and the number of terms, being given, to find the sum of all the terms. RULE II, Multiply the sum of the extremes by the number of terms, and half the product will be the answer. 3. A lady purchased 19 yards of riband, for which she gave Ic. for the first yard, 3c. for the second,... | |
 | James Bryce - 1846 - 352 σελίδες
...bfk dhm ' hence, aei : bfk : : cgi : dhm. 177. PROB. I. To find the sum of an equidifferent series. Multiply the sum of the extremes by the number of terms, and take half the product. Let a be the first term, d the common difference, and s the sum of the series... | |
 | William Vogdes - 1847 - 324 σελίδες
...first term, the last tenu, and the number of terms, being given, to find the sum of all the terms. RULE. Multiply the sum of the extremes by the number...answer. EXAMPLES. 1. The first term of an arithmetical progression is 2, the last term 53, and the number of terms 18 : required the sum of the series ? Thus... | |
 | Daniel Adams - 1848 - 330 σελίδες
...series ; hence, tcken the extremes and the number of terms are given to find the sum of the terms, % RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the terms. EXAMPLES FOR PRACTICE. 2. If the extremes be 5 and 605, and the number of terms 151,... | |
 | Daniel Adams - 1848 - 330 σελίδες
...series ; hence, when the extremes and [he number of terms are, given to fold the sum oj tl/e terms, RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the terms. EXAMPLES FOR PRACTICE. 2. If the extremes be 5 and 605, and the number of terms 151,... | |
 | Daniel Adams - 1848 - 342 σελίδες
...the number of terms are given to find the sum of the terms, RULE. Multiply the sum of the'extremes by the number of terms, and half the product will be the sura of the terms. • EXAMPLES FOR PRACTICE. 2. If the extremes be 5 and 605, and the number of terms... | |
 | Daniel Adams - 1848 - 354 σελίδες
...series ; hence, icken the extremes and the number of terms are given to find the sum oj the terms, RULE. Multiply the sum of the extremes by the number of terms, 'uid half the product will be the sum of the terms. EXAMPLES FOR PRACTICE. 2. If the extremes be 5... | |
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RULE.* — Multiply the sum of the extremes by the number of terms, and half the product will be the answer. 
