 | James Robert Overman - 1923 - 396 σελίδες
...the following way. To multiply a decimal by an integer, multiply as in whole numbers and point off as many decimal places in the product as there are in the multiplicand. A second method of deriving this rule makes use of the pupil's knowledge of concrete numbers to obtain... | |
 | 1923 - 364 σελίδες
...Integers 211 To multiply a decimal number by an integer, multiply as with ordinary numbers and point off as many decimal places in the product as there are in the given decimal number. 1. 18 X 42.6 2. 38 X 4.93 3. 40 X 75.3 4. 12 X 8.95 5. 16 X .328 6. 85 X .084... | |
 | Denver Public Schools - 1924 - 242 σελίδες
...not 392 sq. mi.? Learn this rule: Multiply with decimals just as with whole numbers. Then point off as many decimal places in the product as there are in the multiplier and multiplicand together. P. Practical problems with decimals2 1. Water comprises 0.78... | |
 | James Robert Overman - 1925 - 360 σελίδες
...-and formulate the tentative rule : "To multiply decimals, multiply as whole numbers and point off as many decimal places in the product as there are in the multiplier and multiplicand together." Verification. The tentative method of procedure thus discovered,... | |
 | Harold B. Ray, Arnold V. Doub, Oka Frank Carpenter - 1927 - 88 σελίδες
...by .064. 1003.21 X.064 401284 601926 64.20544 Rule. — Multiply as in whole numbers and point off as many decimal places in the product as there are in the factors taken together EXERCISE 13 1. Add 3.985, 4.06, 98.4763, .0356, and 100.728. 2. Add 13.8505,... | |
 | Cynthia Mitchell - 1998 - 68 σελίδες
...reproducible. 2. Review the multiplication of decimals as follows. a. Multiply as you would with b. Put as many decimal places in the product as there are in the factors combined. whole numbers. 3.2 1.3 5.2 1.3 246 246 62 82 1O66 1O.66 3. Review the division of... | |
 | Gary R. Jensen - 2003 - 402 σελίδες
...the decimal expansions as if there were no decimal point present. and then point off from the right as many decimal places in the product as there are in the multiplier and the multiplicand combined. For example 6.13 x7.24 2452 4 . 613 1226 2 613 tens 4291... | |
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It is evident from what we have seen in adding and subtracting decimals, that in this case there must be as many decimal places in the product, as there are in the multiplicand. It may perhaps be more satisfactory if we analyze it. 
