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 Βιβλία Βιβλία
It is evident from what we have seen in adding and subtracting decimals, that in this case there must be as many decimal places in the product, as there are in the multiplicand. It may perhaps be more satisfactory if we analyze it.
Arithmetic: Being a Sequel to First Lessons in Arithmetic - Σελίδα 213
των Warren Colburn - 1824 - 267 σελίδες
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## Graded Lessons in Number, Μέρος 2

Wm. M. Peck - 1894
...number of decimal places in the product equals the number of decimal places in the other factor, iv. There must be as many decimal places in the product, as there are in both factors, counting from the right of theproduct. 30. Division is the process of separating a number...

## Bradbury's Practical Arithmetic: Combining Oral and Written Exercises

William Frothingham Bradbury - 1895 - 377 σελίδες
...under tlie figure of the multiplier which produces it. 3. Add these partial products and point off as many decimal places in the product as there are in the multiplicand, and the result will be the true product. 62. PROOF. Multiply the multiplier by the multiplicand, and,...

## The Rand-McNally Primary Arithmetic: Principles and Processes Derived by ...

Edwin Crawford Hewett - 1896 - 253 σελίδες
...multiplier had been hundredths; then how many in each? Do you see, then, that there will always be just as many decimal places in the product as there are in the multiplicand and multiplier counted together? Remember this. Now multiply twelve tenths by three hundredths. What...

## The Rand-McNally primary arithmetic

Edwin Crawford Hewett - 1899
...multiplier had been hundredths; then how many in each? Do you see, then, that there will always be just as many decimal places in the product as there are in the multiplicand and multiplier counted together? Remember this. Now multiply twelve tenths by three hundredths. What...

## School Arithmetic: Primary Book

John Marvin Colaw, John Kelley Ellwood - 1900 - 271 σελίδες
...multiply as in whole numbers ? How many decimal places in the 25.2 factors? How many in the product ? There must be as many decimal places in the product as there are in both factors. Find the products: 2. 5 X 3.7 7. 2 X .24 12. 4 X 1.36 3. 7 X 2.3 8. 5 X .13 13. 7 X 3.35...

## Grammar School Arithmetic

Adelia Roberts Hornbrook - 1900 - 416 σελίδες
...integer of four places and find .7 of it. 373. When an integer is multiplied by a decimal there are as many decimal places in the product as there are in the multiplier. Multiply 325 by .7. By .13. By .125. abcde 374. Multiply 275 283 413 671 1289 JJ. A7_ 1.01...

John Appley Ferrell - 1901 - 408 σελίδες
...left of the multiplicand and multiplier, and place the decimal point in the result so that there will be as many decimal places in the product as there are in both multiplicand and multiplier. 1. Multiply .852 by .35. EXAMPLES. Explanation: The multiplicand...

## An Introductory Arithmetic

David Martin Sensenig, Robert F Anderson - 1903 - 256 σελίδες
...this illustration we see that to multiply decimals, we Multiply as in whole numbers, and point off as many decimal places in the product as there are in the multiplicand and multiplier together. 410. Multiply .075 by 45; .075 by .45; .000075 by 420. .075 .075 .000075 45...

## Complete Arithmetic: pt.1-, Τόμος 1

...X .04 = .004 places in the decimal product. When one decimal is multiplied by another, there should be as many decimal places in the product as there are in both factors. 4. .2x3 8. 5 x .12 12. .07 x .07 16. .6x1.2 5. .7x5 9. .3 x .12 13. .22 x .02 17. .08...

## The Silver-Burdett Arithmetics, Book 1-

...multiplicand and multiplier together. 20. To multiply decimals, multiply as in whole numbers, and point off as many decimal places in the product as there are in the multiplicand and multiplier together. 21. Multiply .075 by 45; .075 by .45; .000075 by 420. .075 .075 .000075 45...