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" Guido, with a burnt stick in his hand, demonstrating on the smooth paving-stones of the path, that the square on the hypotenuse of a right-angled triangle is equal to the sum of the squares on the other two sides. "
Euclid's Elements of Geometry: Chiefly from the Text of Dr. Simson, with ... - Σελίδα 118
των Robert Potts - 1868 - 410 σελίδες
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Many Witnesses, One Lord

William Barclay - 2001 - 130 σελίδες
...confidence that something is true that it affects his whole life. To take a simple example, I believe that the square on the hypotenuse of a right-angled triangle is equal to the sum of the squares of the other two sides - but it makes no difference to me. But I believe that...
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Magical Use of Thought Forms: A Proven System of Mental & Spiritual Empowerment

Dolores Ashcroft-Nowicki, J. H. Brennan - 2001 - 276 σελίδες
...that. The name Pythagoras is known to every schoolchild through his famous geometric theorem stating that the square on the hypotenuse of a right-angled triangle is equal to the sum of the squares on the other two sides. But few are taught that the historical Pythagoras was...
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A Theory of Physical Probability

Richard Johns - 2002 - 282 σελίδες
...space. One of the propositions that can be proved from the axioms is the famous theorem of Pythagoras, that the square on the hypotenuse of a rightangled triangle is equal to the sum of the squares on the other two sides. Surprisingly perhaps, it was not until the seventeenth...
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The Role of Imagination in Culture and Society: Owen Barfield's Early Work

Astrid Diener - 2002 - 238 σελίδες
...He does not give reasons for his own point of view, but the causes of yours. You suggest tentatively that the square on the hypotenuse of a right-angled triangle is equal to the sum of the squares on the other two sides, and immediately you blush and wilt and your knees tremble...
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The Many Faces of Philosophy: Reflections from Plato to Arendt

Amélie Oksenberg Rorty - 2003 - 544 σελίδες
...We cannot call that a demonstration which is only a chain of ideas leaving many difficulties. To say that the square on the hypotenuse of a right-angled triangle is equal to the sum of the squares on the other two sides is a demonstration which, however complicated it may...
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Folens Maths Programme

Susan Ball, Sue Briggs, Margaret Mackenzie - 2003 - 212 σελίδες
...are therefore 9, 16 and 25 units 2 . 25 = 9 + 16 This is known as Pythagoras' theorem and it states: the square on the hypotenuse of a right-angled triangle is equal to the sum of the squares on the other two sides. Given the areas of two of the squares, we can calculate...
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The A to Z of Mathematics: A Basic Guide

Thomas H. Sidebotham - 2003 - 488 σελίδες
...the sides of the triangle are a, b, and c units (see figure b), then c2 = a2 + b2 In words we say: "The square on the hypotenuse of a right-angled triangle is equal to the sum of the squares of the other two sides." The theorem of Pythagoras is used for finding the length...
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Records in Stone: Papers in Memory of Alexander Thom

Clive Ruggles - 2003 - 544 σελίδες
...cut to suit 3-4-5 triangles in megalithic inches, but it seems obvious. Now 32 + 42 = 25 = 52 and so 'the square on the hypotenuse of a right-angled triangle is equal to the sum of the squares on the other two sides'. We incline to the idea that Megalithic Man did not...
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New Maths in Action: S3, Τόμος 2

Robin Howat, Graham Meikle, Doug Brown, Ruth Murray, Ken Nisbet - 2004 - 278 σελίδες
...route A -> C —» D -» B c the saving in distance by the tunnel. RECAP Pythagoras' theorem states that: the square on the hypotenuse of a right-angled triangle is equal to the sum of the squares on the two shorter sides. Area A = Area B + Area C => a 2 = b 2 + c 2 Calculating...
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Our Knowledge of Right and Wrong, Τόμος 4

Jonathan Harrison - 2002 - 416 σελίδες
...knowledge that these things were right in some way other than by memory, just as I can only remember that the square on the hypotenuse of a right-angled triangle is equal to the sum of the 1 See GJ Warnock, 'Verification and the Use of Language,' in A Modern Introduction to...
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