 | John Bonnycastle - 1851 - 314 σελίδες
...rule is plainly the reverse of the former, and has its reason in the nature of Common Division. tiply all the numerators together for a numerator, and all the denominators together for a denominator ; and the former product placed over the latter will be the simple fraction required. Note. If two... | |
 | Ezra S. Winslow - 1853 - 264 σελίδες
...product. EXAMPLE. — How may 8 be converted into a fraction whose denominator is 12? 8 X 12 = |J. Ans. To reduce a compound fraction to a simple one....then multiply the. remaining terms as directed above. NOTE. — This last practice is called cancellation, or cancelling the terms. It consists, as has been... | |
 | Noble Heath - 1855 - 468 σελίδες
...3171TV = 980/T = 2190|f Multiplication of Fractions. 206. To find the product "of several fractions, we multiply all the numerators together for a numerator, and all the denominators for a denominator. The fraction thus formed is the product. For example, to multiply | by |. If we... | |
 | Noble Heath - 1856 - 472 σελίδες
...3171T'7 = 980TJf = 2190|f Multiplication of Fractions. 206. To find the product of several fractions, we multiply all the numerators together for a numerator, and all the denominators for a denominator. The fraction thus formed is the product. For example, to multiply f by f. If we... | |
 | James Wood - 1857 - 634 σελίδες
...being divided into 5 '. 5 parts, 39 such parts are to be taken, that is, 7 units and 4 such parts. 16. To reduce a compound fraction to a simple one. RULE. Multiply all the numerators together for a new numerator, and all the denominators for a new denominator. 248 44 Ex. 1. - of - — — ; for one... | |
 | Charles Haynes Haswell - 1858 - 350 σελίδες
...12 to a fraction whose denominator shall be 13. Ans. To reduce a Compound fraction to an equivalent Simple one. * RULE. — Multiply all the numerators...and all the denominators together for a denominator. NOTE. — When there are terms that are common, they may be omitted. EXAMPLE. — Reduce £ of f of... | |
 | William Easton (of Hereford.) - 1859 - 110 σελίδες
...5, 9, 15, 25. 51. Divide }-f by 2, 3, 4, 5, 6, 7, 8, !;. 52. Divide |f by 3, 5, -15, 25. Problem VI. To reduce a compound fraction to a simple one. Rule. Multiply all the numerators together for the new numerator, and all the denominators together for the new denominator, previously cancelling... | |
 | Frederick Augustus Griffiths - 1859 - 426 σελίδες
...29£. Anncer. MULTIPLICATION OF FRACTIONS. Rule. — Reduce mixed numbers to equivalent fractions; then multiply all the numerators together for a numerator,...and all the denominators together for a denominator, which will give the product required. Example. — Multiply $, |, and 2J together. | X | X Q2£ or)... | |
 | Edward Liddell (writer on arithmetic.) - 1861 - 192 σελίδες
...both end in 0, both in 5, or one in 0 and the other in 5, all such uumbers being divisible by 5. 44. To reduce a compound fraction to a simple one. RULE. Multiply all the numerators together for the numerator and all the denominators together for the denominator of the simple fraction. Mixed numbers... | |
 | Oliver Byrne - 1863 - 600 σελίδες
...then y is the answer. For V = 63 -5- 7 = 9, the proof. To reduce a compound fraction to an equivalent simple one. RULE. — Multiply all the numerators...a numerator, and all the denominators together for the denominator, and they will form the simple fraction sought. .When part of the compound fraction... | |
| |
To reduce a compound fraction to an equivalent simple one. RULE. — Multiply all the numerators together for a numerator, and all the denominators together for the denominator, and they will form the simple fraction sought. 
