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" When there are ciphers between the significant figures of the multiplier, we may omit the ciphers, multiplying by the significant figures only, placing the first figure, of each product directly under the figure by which we multiply. EXAMPLES FOR PRACTICE. "
The American Elementary Arithmetic - Σελίδα 77
των James Robinson (of Boston.) - 1858
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...all the figures of the multiplicand successively by each figure of the multiplier, remembering to set the first figure of each product directly under the figure by which you are multiplying, and the sum of these several products will be the total product, or answer required. (85) PROOF. SIMPLE...

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...figures of the multiplier, we may omit the ciphers, multiplying by the significant figures only, placing the first figure of each product directly under the figure by which we multiply. EXAMPLES FOR PRACTICE. OPERATION. 154326 3007 1080282 462978 Product, 464058282 9. Multiply...

Adams's New Arithmetic: Arithmetic, in which the Principles of Operating by ...

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...figures of the multiolier, we may omit the ciphers, multiplying by the significant figures nLy, placing the first figure of each product directly under the figure by which we multiply. 49. 50. 51. 35 30 42 30 35 22 1050 150 84 10x 90 84 69. Multiply 35432 by 14 ; by 15....

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...under tens, and hundreds under hundreds. Multiply the multiplicand by each significant figure of the multiplier, in succession, beginning with units, and...products ; their sum will be the total product required. METHODS OF PROOF. Multiplication is proved by division. If the product be divided by either of the...

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