| Edward Sylvester Ellis - 1886 - 200 σελίδες
...-nfi&W = -00255. Rule for Multiplication of Decimals.—Multiply as in whole numbers, and point off as many decimal places in the product as there are in the multiplicand and multiplier. In case there are not the required number of decimal places in the product, prefix... | |
| Indiana. State Board of Education - 1886 - 360 σελίδες
...-08928. ART. 177.—Rule for Multiplication of Decimals.—Multiply as in whole numbers, and point off as many decimal places in the product as there are in the multiplicand and multiplier. In case there are not the required number of decimal places in the product, prefix... | |
| John Homer French - 1889 - 512 σελίδες
...number of decimal places in the product equals the number of decimal places in the other factor. 5. There must be as many decimal places in the product as there are in the factors. IV. PRINCIPLES OF FRACTIONS. — 1. Multiplying the numerator or dividing the denominator... | |
| Edward Sylvester Ellis - 1889 - 196 σελίδες
...thus : .00255 Bnle for Multiplication of Decimals. — Multiply as in whole numbers, and point off as many decimal places in the product as there are in the multiplicand and multiplier. In case there are not the required number of decimal places in the product, prefix... | |
| Henry Holmes Belfield - 1891 - 362 σελίδες
...7983 by 800 ; by 600 ; by 500. 8. Multiply 82.5 by 3. When the multiplier is an integer, there are as many decimal places in the product as there are in the multiplicand. 9. Multiply $36.25 by 3 ; by 7 ; by 8. 96. 1. Multiply 738 by 146. PROCESS. ANALYSIS. 146=100+40 738... | |
| Gordon Augustus Southworth - 1893 - 200 σελίδες
...0.12? Process. T*ff of T% = т*Д. = 0.24. Process. T6ff XЛ^ = Тй?^ = 0.072. Remark. There will be as many decimal places in the product as there are in both factors. 5. 0.5 of 40 8.0.3x0.09 11. 3% of 900 14.0.7x0.90 6. 5% of 300 9.0.7x0.8 12. 20% of 500... | |
| 1893 - 1066 σελίδες
...are too apt to commit the words of a rule without comprehending their meaning. 2. There should always be as many decimal places in the product as there are in both multiplier and multiplicand, because the denominator of the product contains as many ciphers as... | |
| Wm. M. Peck - 1894 - 310 σελίδες
...number of decimal places in the product equals the number of decimal places in the other factor, iv. There must be as many decimal places in the product, as there are in both factors, counting from the right of theproduct. 30. Division is the process of separating a number... | |
| William Frothingham Bradbury - 1895 - 398 σελίδες
...under tlie figure of the multiplier which produces it. 3. Add these partial products and point off as many decimal places in the product as there are in the multiplicand, and the result will be the true product. 62. PROOF. Multiply the multiplier by the multiplicand, and,... | |
| Edwin Crawford Hewett - 1896 - 312 σελίδες
...multiplier had been hundredths; then how many in each? Do you see, then, that there will always be just as many decimal places in the product as there are in the multiplicand and multiplier counted together? Remember this. Now multiply twelve tenths by three hundredths. What... | |
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