 | Almon Ticknor - 1846 - 276 σελίδες
...terms ; subtract one from that power ; multiply the remainder by the first term ; divide this product by the ratio, less one ; the quotient will be the sum of a geometrical series. 1. The first term is 3, and the ratio 2 ; what is the 6th term? 2x2x2x2x2=2s... | |
 | Joseph Ray - 1848 - 250 σελίδες
...Therefore, *= =— = =•. r—1 r—l Hence, the RULE, FOR FINDING THE SUM OF A GEOMETRICAL SERIES. Multiply the last term by the ratio, from the product...term, and divide the remainder by the ratio less one. EXAMPLES. 1. Find the sum of 10 terms of the progression 2, 6, 18, 54, &,1:. The last term =2x39=2X19683=39366.... | |
 | Jeremiah Day, James Bates Thomson - 1848 - 264 σελίδες
...term in the given series. 373. To find the sum of a geometrical series. Multiply the last term into -the ratio, from the product subtract the first term, and divide the remainder by the ratio less one. Obaer. From the above formula, in connexion with the one. iu Art. 368, there may be the same variety... | |
 | Horatio Nelson Robinson - 1848 - 354 σελίδες
...following rule for the sum of a geometrical series ; RULE. Multiply the last term by the ratio, and from the product subtract the first term, and divide the remainder by the ratio less one. EXAMPLES FOR THE APPLICATION OF EQUATIONS (1) AND (2). 1. Required the sum of 9 terms of the series,... | |
 | Joseph Ray - 1848 - 252 σελίδες
...— — ^— = - =•. r — 1 i — l Hence, the RULE, FOR FINDING THE SUM OF A GEOMETRICAL SERIES. Multiply the last term by the ratio, from the product subtract the frst term, and divide the remainder by the ratio less one. EXAMPLES. 1. Find the sum of 10 terms of... | |
 | Nathan Daboll, David Austin Daboll - 1849 - 260 σελίδες
...last term, (or the extremes,) and the ratio given, to find the sum of the series. RULE. Multiply tke last term by the ratio ; from the product subtract...term, and divide the remainder by the ratio, less 1, and the quotient will be the sum of all the terms. EXAMPLES. 1 . A man bought 6 yards of cloth,... | |
 | Benjamin Naylor - 1850 - 334 σελίδες
...(2) (the first term of the first.) Hence the RULE. product will be the last or greater extreme 2- — multiply the last term by the ratio, from the product...term, and divide the remainder by the ratio less one for the sum of the series, or raise the ratio to a power equal to the number of terms ; subtract one... | |
 | Roswell Chamberlain Smith - 1850 - 314 σελίδες
...when the extremes and ratio are given, to find the sum of the series, we have the following RULE. 21. Multiply the last term by the ratio, from the product...term, and divide the remainder by the ratio, less 1 ; the quotient will be the sum of the series required. 22. If the extremes be 5 and 6,400, and the... | |
 | Horatio Nelson Robinson - 1850 - 256 σελίδες
...gives the following rule for the sum of a series. RULE . — Multiply the last term by the ratio, and from the product subtract the first term, and divide the remainder by the ratio less one. GENERAL EXAMPLES IN GEOMETRICAL PROGRESSION. 1. What is the ratio of the series 2, 6, 18, 54, &c.?... | |
 | Charles Guilford Burnham - 1850 - 350 σελίδες
...find the sum of the series, we have the following l RULES. I. Multiply the last term by the ratio, and from the product subtract the first term, and divide the remainder by the ratio less 1; the quotient will be the answer. II. Divide the difference betiveen the two extremes by the ratio... | |
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Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by the ratio, less 1 ; the quotient will be the sum of the series required. 
