 | Warren Colburn - 1824 - 292 σελίδες
...numbers will be made 10, 100, or 1000 times less than before. ^ Hence to divide by 10, 100, 1000, fyc. cut off from the right of the dividend as many figures as there are zeros in the divisor. The remaining figures will be the quotient, and the figures cut off will be the... | |
 | Bézout - 1825 - 258 σελίδες
...when we have to divide by a number followed by ciphers, we can abridge the operation by separating on the right of the dividend as many figures as there are ciphers ; we divide the part which remains on the left by the significant figures of the divisor, and if there... | |
 | Warren Colburn - 1826 - 264 σελίδες
...numbers will be made 10, 100, or 1000 times less than before. Hence to divide by 10, 100, 1000, Sfc. cut off from the right of the dividend as many figures as there are zeros in the divisor. The remaining figures will be the quotient, and the figures cut off will be the... | |
 | Warren Colburn - 1829 - 258 σελίδες
...will be made 10, 100, or 1000 times less than before. Hence to divide by 10, 100, 1000, ,$*c. cut of from the right of the dividend as many figures as there are zeros in the divisor. The remaining figures will be the quotient, and thi figures cut off will be the... | |
 | W. F. Walker - 1841 - 246 σελίδες
...there are ciphers at the right of the divisor. RULE. I. Write the numbers as in Case III. II. Point off from the right of the dividend as many figures as there are ciphers at the right of the divisor ; divide by the figures at the left of the ciphers only ; annex the figures... | |
 | George Roberts Perkins - 1849 - 346 σελίδες
...remainder. Hence, the true remainder is 20 x 100+94=2094. From the above operations we deduce this RULE. Cut off from the right of the dividend as many figures as there are ciphers at the right of the divisor ; divide what remains by the divisor without the. ciphers at its right.... | |
 | George Roberts Perkins - 1850 - 364 σελίδες
...Hence, the true remainder is 20 x 100+94 = 2094. From the above operations we deduce this RULE. Cat of from the right of the dividend as many figures as there are ciphers at the ri^ht of the divisor; divide what remains by the divisor without the ciphers at its right. To... | |
 | George Roberts Perkins - 1851 - 356 σελίδες
...remainder. Hence, the true remainder is 20 x 100+94=2094. From the above operations we deduce this RULE. Cut off from the right of the dividend as many figures as there are ciphers at the right of the divisor; divide vjhat remains by the divisor without the ciphers at its right.... | |
 | Calvin Tracy - 1851 - 214 σελίδες
...the reverse of multiplication, to divide by these same numbers, viz., 10, TOO, &c., we cut off front the right of the dividend as many figures as there are ciphers in the divisor. The figures on the left of the dividend point, constitute the quotient, and those on... | |
 | Hugo Reid - 1853 - 144 σελίδες
...product as there are at the right of the multiplier. We take a somewhat similar plan in division. We cut off from the right of the dividend as many figures as there are ciphers at the right of the divisor, and then divide in the usual way the remaining figures of the dividend... | |
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Place the sum down as in the last example, then mark off from the right of the dividend as many figures as there are ciphers in the divisor... 
