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" Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend. "
An Introduction to Algebra: With Notes and Observations, Designed for the ... - Σελίδα 21
των John Bonnycastle - 1825 - 312 σελίδες
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The Progressive Higher Arithmetic: For Schools, Academies, and Mercantile ...

Horatio Nelson Robinson - 1860 - 456 σελίδες
...hand of the dividend, as in simple, numbers II. Find the first term of the quotient either by dividing the first term of the dividend by the first term of the divisor, or by dividing the first two terms of the dividend by the first two terms of the divisor ; multiply...

The elements of algebra. [With] Answers

Robert Fowler - 1861
...both the divisor and dividend according to the powers of the same letter (a in the example) ; then to divide the first term of the dividend by the first term of the divisor, place the result in the quotient and multiply the divisor by it ; subtract and proceed similarly with...

Common School Algebra

Thomas Sherwin - 1862
...before; and thus continue, until all the terms of the root are found. \ Remark 2. In dividing, we merely divide the first term of the dividend by the first term of the divisor; and it is manifest, from the manner in which the divisors are obtained, as well as from inspection, that...

Algebra for beginners

Isaac Todhunter - 1863 - 16 σελίδες
...ascending powers of some common letter, or both according to descending powers of some common letter. Divide the first term of the dividend by the first term of the divisor, and put the result for the first term of the quotient; multiply the whole divisor by this term and subtract...

New University Algebra: A Theoretical and Practical Treatise, Containing ...

Horatio Nelson Robinson - 1863 - 420 σελίδες
...quotient similarly arranged. We can therefore obtain this term of the quotient, by simply dividing the first term of the dividend by the first term of the divisor, thus arranged. The operation may then be continued in the manner of long division in Arithmetic ; each...

New Elementary Algebra: in which the First Principles of Analysis are ...

Benjamin Greenleaf - 1863 - 324 σελίδες
...terms, 3а? с -\-6abc -f- 3 V с -{- 3 a c1.-f- 3 6 c1 -f- c", for a remainder or dividend. Dividing the first term of the dividend by the first term of the trial divisor, 3а1, we obtain c, the third term of the root. Adding together three times the square...

New Higher Algebra: An Analytical Course Designed for High Schools ...

Benjamin Greenleaf - 1864 - 394 σελίδες
...Hence, the RULE. Arrange loth dividend and divisor according to the decreasing powers of some letter. Divide the first term of the dividend by the first term of the divisor, and write the result for the first term of the quotient. Multiply the whole divisor by this term, and subtract...

A Treatise on Algebra

Elias Loomis - 1864 - 359 σελίδες
...divisor. (74.) From this investigation we deduce the following BULK FOR THE DIVISION OF POLYNOMIALS. 2. Divide the first term of the dividend by the first term of the divisor, the result will be the first term of the quotient. 3. Multiply the divisor by this term, and subtract...

New University Algebra: A Theoretical and Practical Treatise, Containing ...

Horatio Nelson Robinson - 1864 - 420 σελίδες
...quotient similarly arranged. We can therefore obtain this term of the quotient, by simply dividing the first term of the dividend by the first term of the divisor, thus arranged. The operation may then be continued in the manner of long division in Arithmetic; each...

Ray's Algebra, First Book: Primary Elements of Algebra, for Common ..., Βιβλίο 1

Joseph Ray - 1866 - 240 σελίδες
...divisor with reference to the leading letter, and place the divisor on the right of the dividend. 2. Divide the first term of the dividend by the first term of the divisor, for the first term of the quotient. Multiply the divisor by this term, and subtract the product from...




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