Raise the absolute value of the numerical coefficient to the required power, and multiply the exponent of each letter by the exponent of the required power. College Algebra - Σελίδα 79των James Harrington Boyd - 1901 - 777 σελίδεςΠλήρης προβολή - Σχετικά με αυτό το βιβλίο
| Charles Scott Venable - 1880 - 168 σελίδες
...to a power, Rule. — Raise the coefficient to the required power, observing the rule of the signs, and multiply the exponent of each letter by the exponent of the power. Thus, the square of a"b' is a'b". The third power of - 2ab is - 8a'b'. The fourth power of 2а0V... | |
| Webster Wells - 1885 - 382 σελίδες
...(-3i»4) x (— 37n4) = — 27mu, Аза. From the above examples we derive the following rule : Raise the numerical coefficient to the required power, and...the exponent of the required power. Give to every even power the positive sign, and to every odd ¡lOwer the sign of the quantity itself. • EXAMPLES.... | |
| Webster Wells - 1885 - 370 σελίδες
...(-3m4) X (-3m4) X (-3m4) = -27mu, Ans. From the above examples we derive the following rule : Raise the numerical coefficient to the required power, and...the exponent of the required power. Give to every even power the positive sign, and to every odd power the sign of the quantity itself. EXAMPLES. Write... | |
| Webster Wells - 1885 - 324 σελίδες
...(-3wi4) x (-3m4) x (-3m4) = -27mM, vires, From the above examples we derive the following rule : Raise the numerical coefficient to the required power, and...each letter by the exponent of the required power. EXAMPLES. Write by inspection the values of the following : 3. (-a&V)4. 7. (-bVy. 11. (3a3&4c)e. 4.... | |
| Webster Wells - 1885 - 368 σελίδες
...= (-3m4)x(-3m4)x(-3m4) = -27m12, Ans. From the above examples we derive the following rule : Raise the numerical coefficient to the required power, and...exponent of each letter by the exponent of the required poicer. EXAMPLES. "Write by inspection the values of the following : 3. (-a6V)4. 7. (-6-V)". 11. (3a364с)6.... | |
| Webster Wells - 1889 - 584 σελίδες
...x (—3m4) x (— 3m4) = -27m12, Ans. From the above examples we derive the following rule : Raise the numerical coefficient to the required power, and...each letter by the exponent of the required power. EXAMPLES. Write by inspection the values of the following : 3. (-a&3c3)4. 7. (-&V)5. 11. (3as&4c)в.... | |
| David Martin Sensenig - 1889 - 388 σελίδες
...(62)3 = bt, and (c4)8 = c12 [P. 29] ; hence, the result is — 27a366c12. Therefore, Rule, — Raise the numerical coefficient to the required power, and multiply the exponent of each literal factor by the exponent of the power. EXERCISE 36. Find the value of 1. (a'b<?)5 7. (2 a3 o2... | |
| Webster Wells - 1890 - 560 σελίδες
...• to n factors) (bxb X • • • to ?1 factors) = a" 6". We then have the following rule : liaise the absolute value of the numerical coefficient to...each letter by the exponent of the required power. 110. 1. Square 3 a2 — 2b. By Art. 108, (2), (Art. 109). Note 1. If the first term of the binomial... | |
| Webster Wells - 1890 - 604 σελίδες
...• • • to n factors) (bxbx • • • to n factors) = a"6n. We then have the following rule : Raise the absolute value of the numerical coefficient...power, and multiply the exponent of each letter by tJie exponent of the required power. Gire to every power of a positive term, and to every even power... | |
| Webster Wells - 1897 - 386 σελίδες
...m4) x ( - 3 m4) = - 27 то12 (§ 49) , Ans. From the above examples, we derive the following rule : Raise the absolute value of the numerical coefficient...term, and to every EVEN power of a negative term, the positive sign, and to every ODD x \power of a negative term the negative sign. '• Л 'i „ EXAMPLES.... | |
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