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" If there are more decimal places in the divisor than in the dividend, what do you do ? What will the figures of the quotient then be ? § 132. "
Arithmetic Upon the Inductive Method of Instruction: Being a Sequel to ... - Σελίδα 198
των Warren Colburn - 1834 - 245 σελίδες
Πλήρης προβολή - Σχετικά με αυτό το βιβλίο

The Elementary and Complete Examiner: Or, Candidate's Assistant: Prepared to ...

Isaac Stone - 1869 - 276 σελίδες
...clothes can be made from 34 yds. of cloth, allowing 4.25 yd.*, for each suit? Art. 15G. Ex. 30. G. If there are more decimal places in the divisor than in the dividend, what do you do ? '\Vhat will the figures of the quotient then be? Art. 157. 7. AVhat do you do after...

Common School Arithmetic on the Analytic System: With an Appendix of the ...

Shelton P. Sanford - 1872 - 373 σελίδες
...If there are not enough figures to point off, supply the deficiency by prefixing ciphers. II. When there are more decimal places in the DIVISOR than in the DIVIDEND, make the places equal by annexing ciphers to the dividend before dividing. The quotient in such cases...

The popular educator, Τόμοι 1-2;Τόμος 37

Popular educator - 1876
...whole numbers. Thus, 1203-033 4- -327 = 'Jfëg* -г- ЙЬ = "IP X О = 3679. CASE 3. — Suppose that there are more decimal places in the divisor than in the dividend. Take, for example, 120303-3 -f- '327. 120303-3 -т- -327 = «s*™ -i- ¿£ = Щ&* X 48a = 367900....

Arithmetic. [With] Key

Montagu H. Foster - 1881
...example. There is 1 in the dividend and 1 in the divisor. . - . There are none in the answer. -1)4(1 1 If there are more decimal places in the divisor than in the dividend, there cannot be any decimal places in the answer, but the answer must be made greater, by adding as...

New Complete Arithmetic on the Inductive Method: With Parallel Mental and ...

James William Nicholson - 1885 - 326 σελίδες
...exceed those of the divisor, prefixing ciphers, if necessary, to supply the deficiency. NOTES. - 1. When there are more decimal places in the divisor than in the dividend, make them equal by annexing ciphers to the dividend before dividing. 2. If there is a remainder, ciphers...

Intermediate Arithmetic on the Inductive Method: With Parallel Mental and ...

James William Nicholson - 1885 - 218 σελίδες
...exceed those of the divisor, prefixing ciphers, if necessary, to supply the deficiency NOTES. —I. When there are more decimal places in the divisor than in the dividend, make them equal by annexing ciphers to the dividend before dividing. II. If there is a remainder, ciphers...

An Advanced Arithmetic, Theoretical and Practical

James William Nicholson - 1889 - 395 σελίδες
...those of the divisor, prefixing ciphers, if necessary, to supply the deficiency. NOTES. — 1. When there are more decimal places in the divisor than in the dividend, make them equal by annexing ciphers to the dividend before dividing. 2. If there is a remainder, ciphers...

An Inductive Arithmetic for Intermediate and Higher Grades of Public and ...

Joseph Henry Dunbar - 1902 - 376 σελίδες
...is the answer to the exercise ? Add to the rule previously given so as to provide for division when there are more decimal places in the divisor than in the dividend. SOLUTIONS. Ex.1. Divide 1.6° ° by .008-. (1) (-2) 14) Ex. 2. Divide .2-9 by .3-. 200 .967 3 _ _ «...

The Gilbert Arithmetics, Βιβλίο 3

Charles H. Gleason, Charles Benajah Gilbert - 1910
...the quotient over that of the dividend and divide, prefixing ciphers to the quotient if necessary. If there are more decimal places in the divisor than in the dividend, add enough ciphers to the dividend to equal the difference. If, after adding several ciphers and dividing,...

Gunnery: An Elementary Treatise, Including a Graphical Exposition of Field ...

Jennings Cropper Wise - 1912 - 291 σελίδες
...the divisor; if there be not so many in the quotient, supply the deficiency by prefixing O's. When there are more decimal places in the divisor than in the dividend, annex O's to the latter until the number in both is the same. The quotient will then be a whole number. When...




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