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" If a straight line be bisected and produced to any point, the rectangle contained by the whole line thus produced and the part of it produced, together with the square of... "
The first six books of the Elements of Euclid, with numerous exercises - Σελίδα 38
των Euclides - 1853 - 147 σελίδες
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Examination papers collected by A. Clark as a student and as an examiner

1867
...10. If a straight line be bisected, and produced to any point, the rectangle contained by the whole line thus produced, and the part of it produced, together with the square on half the line bisected, is equal to the square on the straight line which is made up of the half...

The Elements of Euclid for the Use of Schools and Colleges: Comprising the ...

Euclid, Isaac Todhunter - 1867 - 400 σελίδες
...THEOREM. If a straight line be bisected, and produced to any point, the rectangle cjntained by the whole line thus produced, and the part of it produced, together with the tquare on hilf the line bitected, is equal to the square on the straight line which is made up of the...

Annual Report

1868
...If ii straight line IK- bisected and produced to any point, the rectangle coutiiiiu-d by tile whole line thus produced, and the part of it produced, together...which is made up of the half and the part produced 25 5. Divide a given straight line into two parts, so that the rectangle contained by the whole mid...

Euclid's Elements of Geometry: Chiefly from the Text of Dr. Simson, with ...

Robert Potts - 1868 - 410 σελίδες
...part of it produced, together with the square on half the line bisected, i3 equal to the square on the straight line which is made up of the half and the part produced. Let the straight line AB be bisected in C, and produced to the point />• Then the rectangle AD, DB, together with the square...

Report on the examination for admission to the Royal military academy at ...

Woolwich roy. military acad - 1868
...10. If a straight line be bisected and produced to any point, the rectangle contained by the whole line thus produced and the part of it produced, together with the square on half the line bisected, is equal to the square on the straight line which is made up of the half...

Civil service guide

Robert Johnston (F.R.G.S.) - 1869 - 178 σελίδες
...3. If a straight line be bisected, and produced to any point ; the rectangle contained by the whole line thus produced, and the part of it produced, together...square of half the line bisected, is equal to the straight line which is made up of the half and the part produced. 4. The diameter is the greatest straight...

Elements of geometry, containing the first two (third and fourth ..., Μέρος 1

Euclides - 1871
...CB. If a straight line be bisected and produced to any point, the rectangle contained by the whole line thus produced and the part of it produced, together with the square on half the line bisected, is equal to the square on the straight line which is made up of the half...

Geometrical Analysis: Or the Construction and Solution of Various ...

Benjamin Hallowell - 1872 - 279 σελίδες
...the part produced, with the square of half the line bisected, are together equal to the square of the line which is made up of the half and the part produced.* (Let AB be bisected in C, and produced to D ; D } then will AD x DB + CB2 = CD\ or CB2 x DB. Demonstration....

Elements of geometry, containing books i. to vi.and portions of books xi ...

Euclides, James Hamblin Smith - 1872 - 349 σελίδες
...THEOREM. If a straight line be bisected and produced to any point, the rectangle contained by the whole line thus produced and the part of it produced, together with the square on half the line bisected, is equal to the square on the straight line which w made up qfthe half and...

Geometrical Analysis: Or the Construction and Solution of Various ...

Benjamin Hallowell - 1872 - 279 σελίδες
...the part produced, with the square of half the line bisected, are together equal to the square of the line which is made up of the half and the part produced.* f Let AB be bisected in C, and produced to D; D -5 then will AD x DB + CB' = CD\ or CB2 (=CD' — AD...




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