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" ... counted together, equal to the decimal places in the dividend. If there be not figures enough in the quotient to point off, prefix ciphers to supply the deficiency. "
The North American Arithmetic: Part Second, Uniting Oral and Written ... - Σελίδα 122
των Frederick Emerson - 1832 - 216 σελίδες
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Arithmetic. [With] Key

Montagu H. Foster - 1881
...example. There is 1 in the dividend and 1 in the divisor. . - . There are none in the answer. -1)4(1 1 If there are more decimal places in the divisor than in the dividend, there cannot be any decimal places in the answer, but the answer must be made greater, by adding as...

Intermediate Arithmetic on the Inductive Method: With Parallel Mental and ...

James William Nicholson - 1885 - 218 σελίδες
...exceed those of the divisor, prefixing ciphers, if necessary, to supply the deficiency NOTES. —I. When there are more decimal places in the divisor than in the dividend, make them equal by annexing ciphers to the dividend before dividing. II. If there is a remainder, ciphers...

New Complete Arithmetic on the Inductive Method: With Parallel Mental and ...

James William Nicholson - 1885 - 326 σελίδες
...exceed those of the divisor, prefixing ciphers, if necessary, to supply the deficiency. NOTES. - 1. When there are more decimal places in the divisor than in the dividend, make them equal by annexing ciphers to the dividend before dividing. 2. If there is a remainder, ciphers...

An Advanced Arithmetic, Theoretical and Practical

James William Nicholson - 1889 - 395 σελίδες
...exceed those of the divisor, prefixing ciphers, if necessary, to supply the deficiency. NOTES. — 1. When there are more decimal places in the divisor than in the dividend, make them equal by annexing ciphers to the dividend before dividing. 2. If there is a remainder, ciphers...

An Inductive Arithmetic for Intermediate and Higher Grades of Public and ...

Joseph Henry Dunbar - 1902 - 376 σελίδες
...then, is the answer to the exercise ? Add to the rule previously given so as to provide for division when there are more decimal places in the divisor than in the dividend. SOLUTIONS. Ex.1. Divide 1.6° ° by .008-. (1) (-2) 14) Ex. 2. Divide .2-9 by .3-. 200 .967 3 _ _ «...

The Gilbert Arithmetics, Βιβλίο 3

Charles H. Gleason, Charles Benajah Gilbert - 1910
...the quotient over that of the dividend and divide, prefixing ciphers to the quotient if necessary. If there are more decimal places in the divisor than in the dividend, add enough ciphers to the dividend to equal the difference. If, after adding several ciphers and dividing,...

Gunnery: An Elementary Treatise, Including a Graphical Exposition of Field ...

Jennings Cropper Wise - 1912 - 291 σελίδες
...those in the divisor; if there be not so many in the quotient, supply the deficiency by prefixing O's. When there are more decimal places in the divisor than in the dividend, annex O's to the latter until the number in both is the same. The quotient will then be a whole number....

Shop Mathematics ...: Shop arithmetic

Earle Bertram Norris, Kenneth Gardner Smith, Ralph Thurman Craigo - 1912
...answer is simply 4. The decimal point would come after the 4 where it would, of course, be useless. If there are more decimal places in the divisor than in the dividend, add ciphers at the right of the decimal part of the dividend as far as necessary. In counting the decimal...

Shop Mathematics ...: Shop arithmetic

Earle Bertram Norris, Kenneth Gardner Smith, Ralph Thurman Craigo - 1912
...answer is simply 4. The decimal point would come after the 4 where it would, of course, be useless. If there are more decimal places in the divisor than in the dividend, add ciphers at the right of the decimal part of the dividend as far as necessary. In counting the decimal...

Handbook for Quartermasters: Pts. I to V. I. Administrative. II. Supply. III ...

United States. Army. Quartermaster Corps - 1930 - 1192 σελίδες
...those in the divisor; if there be not so many in the quotient, supply the deficiency by prefixing O's. When there are more decimal places in the divisor than in the dividend annex O's to the latter until the number in both is the same. The quotient will than be a whole number....




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