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" Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer. "
The North American Arithmetic: Part Second, Uniting Oral and Written ... - Σελίδα 129
των Frederick Emerson - 1832 - 216 σελίδες
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A Complete System of Theoretical and Mercantile Arithmetic: Comprehending a ...

George G. Carey - 1818 - 574 σελίδες
...means. Hence results the following rule for finding a fourth proportional to three given numbers. BULE. Multiply the second and third terms together, and divide the product by the first, and the quotient is the answer, or fourth proportional. EXAMPLE I. Required a fourth proportional to...

A Treatise of Practical Arithmetic

Robert Patterson - 1819 - 156 σελίδες
...we have the equation ad = be, and this divided by a, will give d = —. In words — multiply the a second and third terms together, and divide the product by the first, and the quotient will be the fourth, or term required. II. IN ALLIGATION ALTERNATE. Let a, A, = the...

The Scholar's Arithmetic: Designed for the Use of Schools in the United States

Jacob Willetts - 1822 - 191 σελίδες
...DIRECT PROPORTION. RULE. Prepare the given terms, if necessary, and state them as ia whole numbers : multiply the second and third terms together, and divide the product by the first : Or, Invert the first term and multiply the three together, as in Multiplication. EXAMPLES. i . If...

The American Tutor's Assistant Revised, Or, A Compendious System of ...

Zachariah Jess - 1824 - 210 σελίδες
...dols. ' A " 5 ' 3 : 6 :: 9 : 1 8 more requiring more I 20 : 40 :: 3 : 10 less requiring less RULE. Multiply the second and third terms together, and divide the product by the first ; the quotient will be the fourth term, or answer ; in the same name with the second. PROOF. Invert...

The Teachers' Assistant: Or a System of Practical Arithmetic

Stephen Pike - 1824 - 198 σελίδες
...THREE, IN VULGAR FRACTIONS. Prepare the given terms, if necessary, and state them as in whole numbers ; multiply the second and third terms together, and divide the product by the first. Or, Invert the dividing term, and multiply the three terms together, as in Multiplication. EXAMPLES....

The New Federal Calculator, Or, Scholar's Assistant: Containing the Most ...

Thomas Tucker Smiley - 1825 - 180 σελίδες
...second terms to the same denomination, and to the lowest denomination mentioned in either oi them. 3. Multiply the second and third terms together, and divide the product by the first term; the result will be-tbe fourth term OF answer in the same denomination to which the third term was reduced....

Temple's Arithmetick: A Concise Introduction to Practical Arithmetick; in ...

Samuel Temple - 1825 - 107 σελίδες
...mentioned. Having properly stated the question, multiply the second and third terms into each other, and divide the product by the first term ; the quotient will be the answer, or number, sought. JVo/e 3. The answer always come: in the same denomination with the middle...

Pike's System of Arithmetick Abridged: Designed to Facilitate the Study of ...

Nicolas Pike, Dudley Leavitt - 1826 - 200 σελίδες
...kind, the first term ; and that which is of the same name or kind with the answer, the second term. 2. Multiply the second and third terms together, and divide the product by the first term, and the quotient will be the fourth term, or answer. The notes under the general rule are applicable...

The Youth's Assistant in Theoretick and Practical Arithmetic

Zadock Thompson - 1826 - 164 σελίδες
...the same kind, the first term, and that which is of the same kind as the answer, the second term. 2.f Multiply the second and third terms together, and divide the product by the first, the quotient will be the answer. EXAMPLE. — If 8lb. of sugar cost $1.00, what will 401b-. of sugar...

Syllabus of Philosophical Lectures, Given During Each Half Year: At Poplar ...

Poplar House Academy - 1826 - 92 σελίδες
...necessary, to the same denomination, and the third to the lowest denomination mentioned in it. Then, multiply the second and third terms together, and divide the product by the first, and the quotient will be the answer, in the same denomination that the third term was reduced to ;...




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