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" The square described on the hypothenuse of a right-angled triangle is equivalent to the sum of the squares described on the other two sides. "
A Complete Epitome of Practical Navigation, and Nautical Astronomy ... - Σελίδα 37
των John William Norie, J. W. Saul - 1917 - 595 σελίδες
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Questions and Exercises on Stewart's Lessons in Elementary Physics

George Anthony Hill - 1880 - 204 σελίδες
...adjacent segment. (20) The square described upon the hypothenuse of a right triangle is equivalent to the sum of the squares described on the other two sides. (21) Similar triangles (or polygons) are to each other as the squares of their homologous sides. (22)...

The Addresses and Journal of Proceedings of the National Educational Association

National Educational Association (U.S.) - 1881 - 372 σελίδες
...student through his sight that the square described on the hypothenuse of a right-angled triangle, is equal to the sum of the squares described on the other two sides, although we may not make him understand the logical demonstration. We can convince even a child, with...

Elements of Geometry, After Legendre, with a Selection of Geometrical ...

Charles Scott Venable - 1881 - 380 σελίδες
...PROPOSITION XI. THEOREM. The square described on the hypothemtse of a right angled triangle is equivalent to the sum of the squares described on the other two sides. Let the triangle ABC be right angled at A. Having formed squares on the three sides, let fall, from A,...

Proceedings, Abstracts of Lectures and a Brief Report of the Discussions of ...

National Education Association of the United States - 1881 - 372 σελίδες
...student through his sight that the square described on the hypothenuse of a right-angled triangle, is equal to the sum of the squares •described on the other two sides, although we may not make him understand the logical demonstration. We can convince even a child, with...

The Competitor, Τόμοι 1-2

1882 - 486 σελίδες
...ara assumed in the proof. 8. Prove that if the square described on one of the siles of a triangle be equal to the sum of the squares described on the other two sides of it, the angle contained by these two sides is a right angle. 4. Prove that if a st aight line be...

The Eclectic Question Book: Designed to Assist Pupils in Reviewing Their ...

Alexander Duncan - 1882 - 180 σελίδες
...geometrical demonstration, that the square described upon the hypothenuse of a right-angled triangle is equal to the sum of the squares described on the other two sides? Art. 386. 8. Two sides of a right-angled triangle being given, how do you find the other two? Art....

Gibson's London matriculation guide, by J. Gibson [and others].

1882 - 376 σελίδες
...FRS, and BENJAMIN WHXIAMSON, ESQ., MA, FRS 1. If the square described on one side of a triangle be equal to the sum of the squares described on the other two sides, prove that the angle contained by these sides is a right angle. 2. Prove that the quadrilateral formed...

Geometry for schools, comprising books i. and ii. of Euclid, with some ...

Euclides - 1883 - 176 σελίδες
...right angles to one another. PROP. 48. THEOR. If the square described on one side of a triangle be equal to the sum of the squares described on the other two sides of it, the angle contained by these two sides is a right angle. Given A ABC having sq. on BC = squares...

The Elements of Euclid for the Use of Schools and Colleges: Comprising the ...

Euclid, Isaac Todhunter - 1883 - 428 σελίδες
...obtuse. For the angle cannot be a right angle, since the square described on the first side would then be equal to the sum of the squares described on the other two sides, by I. 47 ; and the angle cannot be acute, since the square described on the first side would then be...

Elementary Geometry: Including Plane, Solid, and Spherical Geometry, with ...

Edward Olney - 1883 - 344 σελίδες
...186. 376. Theorem.—The square described on the hypotenuse of a right-angled triangle is equivalent to the sum of the squares described on the other two sides. We are to prove that AB 2 = AC' + CB 9 . For, let fall the perpendicular CD, and by (374, 2cl) we have...




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