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 Βιβλία Βιβλία FK : in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK : therefore the five straight lines FG, FH, FK, FL, FM are equal to one another : wherefore the circle described from the centre F, at the distance of... Euclid's Elements of Geometry: The First Six, the Eleventh and Twelfth Books - Σελίδα 183
των Euclid - 1765 - 464 σελίδες
Πλήρης προβολή - Σχετικά με αυτό το βιβλίο ## Euclid's Elements of geometry, transl. To which are added, algebraic ...

Euclides - 1826
...manner it may be demonstrated that each of the sides FL, FM, FG, is equal to each of the sides FH, FK ; therefore the five right lines FG, FH, FK, FL, FM, are equal to one another. Wherefore with centre F and distance any one of them FG, FH, FK, FL, FM, the circle described will both pass... ## Elements of Geometry, Containing the First Six Books of Euclid

Euclid - 1826 - 180 σελίδες
...manner it may be demonstrated that each of the sides FL, FM, FG, is equal to each of the sides FH, FK ; therefore the five right lines FG, FH, FK, FL, FM, are equal to one another. Wherefore with centre F and distance any one of them FO, FH, FK, FL, FM, the circle described will both pass... ## The Elements of Euclid: The Errors by which Theon, Or Others, Have Long ...

Robert Simson - 1827 - 513 σελίδες
...perpendicular FH is equal to the perpendicular FK : in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK : therefore the five straight lines FG, FH, FK, FL, FM are equal to one another : wherefore the circle described from the... ## The Elements of Euclid: Viz. the First Six Books, Together with the Eleventh ...

Euclid - 1835 - 513 σελίδες
...perpendicular FH is equal to the perpendicular FK : In the same manner, it may be demonstrated, that FL, FM, FG are each of them equal to FH or FK : Therefore the five straight lines FG, FH, FK, FL, FM are equal to one another : Wherefore the circle described from the... ## Elements of Plane Geometry According to Euclid

Andrew Bell - 1837 - 240 σελίδες
...perpendicular FH is equal to the perpendicular FK. In the same manner, it may be demonstrated that FL, FM, FG, are each of them equal to FH or FK ; therefore the five straight lines FG, FH, FK, FL, FM, are equal to one another ; wherefore the circle described from the... ## The Elements of Euclid; viz. the first six books,together with the eleventh ...

Euclides - 1841 - 351 σελίδες
...perpendicular FH is equal to the perpendicular FK. In the same manner it may be demonstrated that FL, FM, FG are each of them equal to FH or FK: therefore the five straight lines FG, FH, FK, FL, FM are equal to one another: wherefore the circle described from the... ## Elements of Geometry: Containing the First Six Books of Euclid, with a ...

John Playfair - 1842 - 317 σελίδες
...perpendicular FH is equal to the perpendicular FK : in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK ; therefore the five straight lines FG, FH, FK, FL, FM are equal to one another ; wherefore the circle described from the... ## Euclid's Elements of geometry [book 1-6, 11,12] with explanatory notes ...

Euclides - 1845
...perpendicular FH is equal to the perpendicular FA": in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK: therefore the five straight lines FG, FH, FK, FL, FM are equal to one another : wherefore the circle described from the... ## Euclid in Paragraphs: The Elements of Euclid: Containing the First Six Books ...

Euclid - 1845 - 199 σελίδες
...perpendicular FH is equal to the perpendicular FK : In the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK ; Therefore the five straight lines FG, FH, FK, FL, FM are equal to one another; wherefore the circle described from the... ## Elements of Geometry: Containing the First Six Books of Euclid, with a ...

Euclid, John Playfair - 1846 - 317 σελίδες
...perpendicular FH is equal to the perpendicular FK : in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK ; therefore the five straight lines FG, FH, FK, FL, FM are equal to one another ; wherefore the circle described from the...