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" I. Annex ciphers to the numerator, and divide by the denominator. II. Point off as many decimal places in the quotient as there are ciphers used. "
The Normal Union Arithmetic: Graded Course - Σελίδα 131
των Edward Brooks - 1877 - 230 σελίδες
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Robinson's New Rudiments of Arithmetic

Horatio Nelson Robinson - 1892 - 236 σελίδες
...as before, or, 4)3.00 we obtain 5 hundredths. The sum of .75, Ans. the quotients is .75, Ans. Rule. I. Annex ciphers to the numerator, and divide by the...denominator. II. Point off as many decimal places in the result as are equal to the number of ciphers annexed. Reduce to decimals : • 2. \. 3. |. 4. f. 5....

Standard Arithmetic: Embracing a Complete Course for Schools and Academies

William James Milne - 1892 - 440 σελίδες
...hundredths + 5 thousandths, or .875. RULE. — Annex ciphers to the numerator and divide by the denominator. Point off as many decimal places in the quotient as there are ciphers annexed. 1. In many cases the division is not exact. In such instances the remainder may be expressed...

Elementary Arithmetic

John Williston Cook, Nebraska C. Cropsey - 1893 - 316 σελίδες
...result is obtained by annexing ciphers to the numerator, dividing by the denominator, and pointing off as many decimal places in the quotient as there are ciphers annexed.' 4)3.00 .75 Change | to an equivalent decimal. 6)5.000 or, 6 ) 5.000 ~.833J .833+ If, after...

Elements of Arithmetic: For Primary and Intermediate Classes in Public and ...

William James Milne - 1893 - 252 σελίδες
...reduced to a decimal by annexing ciphers to the numerator and dividing by the denominator, and pointing off as many decimal places in the quotient as there are ciphers annexed. In many cases the division is not exact. In such instances the remainder may be expressed...

New Practical Arithmetic: In which the Science and Its Applications are ...

Henry B. Maglathlin - 1894 - 370 σελίδες
...dividend over that in the divisor. RULE. If the divisor is a whole number, divide as in wholt numbers, and point off as many decimal places in the quotient as there are such places in the dividend. Or, If the divisor is not a whole number, divide by its numerator, and...

The Normal Standard Arithmetic: By Analysis and Induction, Designed for ...

Edward Brooks - 1895 - 424 σελίδες
...hundredths equal 40 thousandths ; \ of 40 thousandths is 5 thousandths. Therefore, f equals .625. Rule. — I. Annex ciphers to the numerator, and divide by the...decimal places in the quotient as there are ciphers annexed. 1. When the division will not terminate, the common fraction cannot be exactly expressed by...

The Normal Rudiments of Arithmetic, Oral and Written: Designed for Primary ...

Edward Brooks - 1895 - 248 σελίδες
....75. Hence the following method : 1. Annex ciphers to the numerator, and divide by the denominator. 2. Point off as many decimal places in the quotient as there are ciphers annexed. When the division is not exact, the remainder may be expressed as a common fraction, or the...

A Common School Arithmetic

Bothwell Graham - 1895 - 240 σελίδες
...etc. ; £ of 3.00 = .75. 4 4 RULE. — Annex zeros to the numerator and divide by the denominator. Point off as many decimal places in the quotient as there are zeros annexed. Reduce to decimals : 2. *. 6. f. 10. TV 14. .37*. 3. \. 7. f. 11. ¿r- 15- -27f 4. f....

Robinson's New Higher Arithmetic: For High Schools, Academies, and ...

Horatio Nelson Robinson - 1895 - 526 σελίδες
...number, place a decimal point in the quotient as soon as the decimal point in the dividend is readied, or point off as many decimal places in the quotient as there are in the dividend. IV. If tlie division is not exact, place the final remainder in the quotient, and...

An Elementary Treatise on Electric Power and Lighting: Arithmetic ...

International Correspondence Schools - 1897 - 346 σελίδες
...the number of decimal places in the divisor from the number of decimal places in the dividend, and point off 'as many decimal places in the quotient as there are units in the remainder thus found. EXAMPLE.— Divide .625 by 25. divisor dividend quotient SOLUTION....




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