| Royal Military Academy, Woolwich - 1853 - 400 σελίδες
...BC divides the parallellogram ACDB into two equal parts. QED PROPOSITION XXXV. THEOR. Parallelograms upon the same base, and between the same parallels, are equal to one another. Let the parallelograms ABCD, KBCF be upon the same base BC, and between the same parallels AF; BC : the parallelogram... | |
| Euclides - 1853 - 176 σελίδες
...divides the parallelogram a С db into two equal parts. QED PROPOSITION XXXV. — THEOREM. Parallelograms upon the same base, and between the same parallels, are equal to one another. LET the parallelograms abСd, ebСf (see the second figure) be upon the same base b С, andbetween the same... | |
| Thomas Lund - 1854 - 520 σελίδες
...FG is equal to that ratio (170), and join DH. Then DHG is the triangle required. For BDC, BDF, being triangles upon the same base and between the same parallels, are equal to one another (41). Also A.ADE — &ADG; .'.adding to these equals the AABD, it is evident that ADGF = the polygon... | |
| John Playfair - 1855 - 334 σελίδες
...same EBCH : Therefore also the parallelogram ABCQ it equal to EFGH. PROP. XXXVII. THEOR. Trioi gles upon the same base, and between the same parallels,...parallels, AD, BC : The triangle ABC is equal to the triangle DBC. E AB Produce AD both ways to the points E, F, and through B draw (31. 1.) BE parallel... | |
| Euclides - 1855 - 270 σελίδες
...only which are at the vertices of any two of its opposite angles. PROP. XXXV. THEOREM. Parallelograms upon the same base, and between the same parallels, are equal to one another. Let the parallelograms AС, B Г be upon the same base B С, and and between the same parallels AF, BС. The... | |
| Robert Potts - 1855 - 1050 σελίδες
...times as great ? The line joining the bisections of two sides of a triangle is parallel to the base. 3. Triangles upon the same base, and between the same parallels are equal to one another. The lines joining the bisections of the sides of any quadrilateral figure, together constitute a parallelogram.... | |
| Great Britain. Committee on Education - 1855 - 976 σελίδες
...equal, each to each, namely, those to which the equal sides are opposite, 2. Parallelograms on the same base and between the same parallels are equal to one another. 3. In any triangle, if the square of one of the sides is equal to the squares of the two other sides,... | |
| Euclides - 1856 - 168 σελίδες
...BCD; therefore, the diameter BC divides the parallelogram into two equal parts. XXXVII. Parallelograms upon the same base and between the same parallels are equal to one another. Let the parallelograms ABCD, EBCF (Fig. 29) be upon the same base BC, and between the same parallels AF, BC... | |
| Cambridge univ, exam. papers - 1856 - 252 σελίδες
...College. WILLIAM HENRY BESAHT, MA St John's College. TUESDAY, January 6, 1857. 9... 12. 1. PARALLELOGRAMS upon the same base, and between the same parallels, are equal to one another. ABC is an isosceles triangle, of which A is the vertex : AB, AC, are bisected in D and E respectively... | |
| William Pease - 1856 - 108 σελίδες
...to meet these perpendiculars, and the required rectangle will be formed. REASON : " Parallelograms, upon the same base, and between the same parallels," are equal to each other. (Euclid, Book I. Prop. 35.) PROBLEM LXX. To make a rectangle, one of its sides being given,... | |
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