 | John Playfair - 1819 - 350 σελίδες
...EBCH : Therefore also the parallelogram ABCD is equal to EFGH. Wherefore, parallelograms, &c* Q,. ED PROP. XXXVII. THEOR. Triangles upon the same base,...the same base BC, and between the same parallels AD, ^_ BC : The triangle ABC, is e- •& . A. .IP . . . J to the triangle DBC. Produce AD both ways to... | |
 | John Playfair - 1819 - 354 σελίδες
...EBCH : Therefore also the parallelogram ABCD is equal to EFGH. Wherefore, parallelograms, &c. Q, ED PROP. XXXVII. THEOR. Triangles upon the same base,...between the same parallels, are equal to one another. AD Let the triangles ABC, DBC be upon the same base BC, and between the same parallels AD, BC : The... | |
 | Euclid, Robert Simson - 1821 - 514 σελίδες
...diameter BC divides the parallelogram ACDB into two equal parts. QED PROP. XXXV. THEOR. PARALLELOGRAMS upon the same base, and between the same parallels, are equal to one another.* "Let the parallelograms ABCD, EBCF be upon the same base BC, and between the same parallels AF, BC; the parallelogram... | |
 | Peter Nicholson - 1825 - 1046 σελίδες
...divides the parallelogram ACDB into two eqoal parts, QED Proposition XXXV. Theorem. Parallelograms upon the same base, and between the same parallels, are equal to one another. Let the parallelograms ABCD, EBCF be upon the same base BC, and between the same parallels AF BC ; the parallelogram... | |
 | Euclid, John Playfair - 1826 - 326 σελίδες
...Therefore also the parallelogram ABCD is equal to EFGH. Wherefore, parallelograms, &e. QED ' .1 3 » -^ PROP, XXXVII. THEOR. Triangles upon the same base,...between the same parallels AD, BC : The triangle ABC, is e- E AD p3 qual to the triangle DBC. Produee AD both ways to the points E, F, and through B draw (31.... | |
 | Euclides - 1826 - 226 σελίδες
...shall the two trapeziums be equal to one another. PROPOSITION XXXVII. THEOREM. Triangles constituted upon the same base, and between the same parallels, are equal to one another. » 3i. i. parallel to сл, " and through c draw CF, parallel to в D. Therefore each of them EBCA,... | |
 | Euclid - 1826 - 234 σελίδες
...Therefore triangles, &c. QED PROPOSITION XXXVIII. THEOREM. Triangles constituted upon equal bases, and between the same parallels, are equal to one another. Let the triangles ABC, DCE, be constituted upon equal bases вс, CE, and <? A n н between the same parallels BE, AD. The... | |
 | Robert Simson - 1827 - 546 σελίδες
...EBCH : therefore the parallelogram ABCD is equalf t 1 Ax. to EFGH. Wherefore parallelograms, &c. QEJO. PROP. XXXVII. THEOR. Triangles upon the same base, and between the same parallels, am equal to one another. 33. 1. Def. 34. . 35. 1. Let the triangles ABC, DBC, be upon the... | |
 | Euclid, Robert Simson - 1829 - 548 σελίδες
...same EBCH; therefore also the parallelogram ABCD is equal to EFGH. Wherefore parallelograms, &c. QED PROP. XXXVII. THEOR. TRIANGLES upon the same base,...the same base BC, and between the same parallels AD, E AD F BC : the triangle ABC is equal to the triangle DBC. Produce AD both ways to the points E, F,... | |
 | John Playfair - 1829 - 210 σελίδες
...to each other. Therefore, parallelograms &c. QED ED. PROPOSITION XXXVII. THEOREM, Triangles on the same base, and between the same parallels, are equal to one another; that is, their surfaces are equal. Let the triangles ABC, DBC be on the same base BC, and between the... | |
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Parallelograms upon the same base and between the same parallels, are equal to one another. 
